Nim or not Nim?
结论
Mult−NimMult-NimMult−Nim博弈:有nnn堆石子,两个人可以从任意一堆石子中拿任意多个石子(不能不拿)或把一堆数量不少于22石子分为两堆不为空的石子,没法拿的人失败,问谁会胜利。
结论SG(x)=x−1[xmod4==0],x+1[xmod4==3],x[others]SG(x) = x - 1[x \bmod 4 == 0], x + 1[x \bmod 4 == 3], x[others]SG(x)=x−1[xmod4==0],x+1[xmod4==3],x[others]
代码
/*Author : lifehappy
*/
#pragma GCC optimize(2)
#pragma GCC optimize(3)
#include <bits/stdc++.h>#define mp make_pair
#define pb push_back
#define endl '\n'
#define mid (l + r >> 1)
#define lson rt << 1, l, mid
#define rson rt << 1 | 1, mid + 1, r
#define ls rt << 1
#define rs rt << 1 | 1using namespace std;typedef long long ll;
typedef unsigned long long ull;
typedef pair<int, int> pii;const double pi = acos(-1.0);
const double eps = 1e-7;
const int inf = 0x3f3f3f3f;inline ll read() {ll f = 1, x = 0;char c = getchar();while(c < '0' || c > '9') {if(c == '-') f = -1;c = getchar();}while(c >= '0' && c <= '9') {x = (x << 1) + (x << 3) + (c ^ 48);c = getchar();}return f * x;
}int sg(int x) {if(x % 4 == 0) return x - 1;else if(x % 4 == 3) return x + 1;return x;
}int main() {// freopen("in.txt", "r", stdin);// freopen("out.txt", "w", stdout);// ios::sync_with_stdio(false), cin.tie(0), cout.tie(0);int T = read();while(T--) {int n = read(), ans = 0;for(int i = 1; i <= n; i++) {ans ^= sg(read());}puts(ans ? "Alice" : "Bob");}return 0;
}