2019独角兽企业重金招聘Python工程师标准>>> 
SELECT t.building,t.unit,t.room,t.ashcan
,(SELECT COUNT(a.resident_id) from t_address_book a
where a.village_id = t.village_id AND a.building = t.building
and a.room = t.unit and a.house = t.room
and a.`status` = 1
) AS regisNum
from t_village_standard t
where t.village_id = 317
and t.`status` = 1
