2023每日刷题（六）

Leetcode—2331.计算布尔二叉树的值

递归实现代码

/*** Definition for a binary tree node.* struct TreeNode {*     int val;*     struct TreeNode *left;*     struct TreeNode *right;* };*/
bool evaluateTree(struct TreeNode* root){struct TreeNode* p = root;if(p == NULL) {return NULL;} else if(p->left == NULL) {if(p->val == 0) {return false;} else {return true;}} bool left = evaluateTree(p->left);bool right = evaluateTree(p->right);if(p->val == 2) {return left || right;} else if(p->val == 3){return left && right;} else if(p->val == 0) {return false;} else {return true;}
}

运行结果

改良版代码

/*** Definition for a binary tree node.* struct TreeNode {*     int val;*     struct TreeNode *left;*     struct TreeNode *right;* };*/
bool evaluateTree(struct TreeNode* root){if(!root->left) {return root->val;}return (root->val == 2 ? (evaluateTree(root->left) || evaluateTree(root->right)): (evaluateTree(root->left) && evaluateTree(root->right)));
}

运行结果

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