1. 题目

Table: Activity

+--------------+---------+
| Column Name  | Type    |
+--------------+---------+
| player_id    | int     |
| device_id    | int     |
| event_date   | date    |
| games_played | int     |
+--------------+---------+
(player_id, event_date) 是这个表的两个主键

这个表显示的是某些游戏玩家的游戏活动情况
每一行是在某天使用某个设备登出之前登录并玩多个游戏（可能为0）的玩家的记录
请编写一个 SQL 查询，描述每一个玩家首次登陆的设备名称

查询结果格式在以下示例中：

Activity table:
+-----------+-----------+------------+--------------+
| player_id | device_id | event_date | games_played |
+-----------+-----------+------------+--------------+
| 1         | 2         | 2016-03-01 | 5            |
| 1         | 2         | 2016-05-02 | 6            |
| 2         | 3         | 2017-06-25 | 1            |
| 3         | 1         | 2016-03-02 | 0            |
| 3         | 4         | 2018-07-03 | 5            |
+-----------+-----------+------------+--------------+Result table:
+-----------+-----------+
| player_id | device_id |
+-----------+-----------+
| 1         | 2         |
| 2         | 3         |
| 3         | 1         |
+-----------+-----------+

来源：力扣（LeetCode）
链接：https://leetcode-cn.com/problems/game-play-analysis-ii
著作权归领扣网络所有。商业转载请联系官方授权，非商业转载请注明出处。

2. 解题

# Write your MySQL query statement below
select a.player_id, a.device_id
from Activity a,(   select *, min(event_date) mindatefrom Activitygroup by player_id) t
where a.player_id = t.player_id and a.event_date = t.mindate

or

# Write your MySQL query statement below
select player_id, device_id
from activity
where (player_id, event_date) in (select player_id, min(event_date)from activitygroup by player_id)

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