题目大意：给一个字符串，求字符串的所有前缀的最小后缀；

思路：主要还是要理解Lyndon串的算法的整一个过程

 参考：搬运来自

#include <iostream>
#include <cstdio>
#include <fstream>
#include <algorithm>
#include <cmath>
#include <deque>
#include <vector>
#include <queue>
#include <string>
#include <cstring>
#include <map>
#include <stack>
#include <set>
#include <cstdlib>
#define INF 0x3f3f3f3f3f3f3f3f
#define inf 0x3f3f3f3f
#define FILL(a,b) (memset(a,b,sizeof(a)))
#define re register
#define lson rt<<1
#define rson rt<<1|1
#define lowbit(a) ((a)&-(a))
#define ios std::ios::sync_with_stdio(false);std::cin.tie(0);std::cout.tie(0);
#define fi first
#define rep(i,n) for(int i=0;(i)<(n);i++)
#define rep1(i,n) for(int i=1;(i)<=(n);i++)
#define se second
#define scd(a) scanf("%d",&a)
#define scdd(a,b) scanf("%d%d",&a,&b)
#define scddd(a,b,c) scanf("%d%d%d",&a,&b,&c)
#define ac cout<<ans<<"\n"
#define F(x) ((x)/3+((x)%3==1?0:tb))
#define G(x) ((x)<tb?(x)*3+1:((x)-tb)*3+2)
#define pb push_back
using namespace std;
typedef long long  ll;
typedef unsigned long long  ull;
typedef pair<ll,ll> pii;
int dx[4]= {-1,1,0,0},dy[4]= {0,0,1,-1};
const ll mod=1e9+7;
const ll N =2e6+10;
const ll M =250000;
const double eps = 1e-4;
//const double pi=acos(-1);
ll qk(ll a,ll b){ll ans=1;while(b){if(b&1) ans=(ans*a)%mod;a=(a*a)%mod;b/=2;}return ans%mod;}
int n;
int d[N];
char s[N];
void sovle(){cin>>(s+1);n=strlen(s+1);int i=1;d[1]=1;ll ans=0;while(i<=n){int j=i,k=i+1;while(k<=n&&s[j]<=s[k]){if(s[j]==s[k]) d[k]=d[j]+(k-j),j++;else {d[k]=i;j=i;}k++;}d[k]=k;while(i<=j) i+=k-j;}for(int i=n;i>=1;i--) ans=(ans*1112%mod+d[i])%mod;cout<<ans<<endl;
}
int main()
{
#ifdef LOCALfreopen("in.txt", "r", stdin);
#elseiosint t=1;cin>>t;while(t--) sovle();
#endif // LOCALreturn 0;
}