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Problem statement: Write a C program to find odd or even no using bitwise operators.

问题陈述：编写一个C程序以使用按位运算符查找奇数或什至无 。

Solution: We can use bitwise operator here to solve the problem.

解决方案：我们可以在这里使用按位运算符来解决问题。

Solution

解

    Let n be a number
n &1 = 0000000d where d is the LSB of n 
So, 
If LSB ==1
It's odd number
Else
Even no

To understand the concept of "LSB" & bitwise operators please read: Bitwise Operators and their working with Examples in C

要了解“ LSB”和按位运算符的概念，请阅读： 按位运算符及其在C语言中与Example一起使用

Example:

例：

    Let n be 7 //00000111
n & 1 = 1 
00000111(7) & 00000001(1) =00000001 (1)
Thus it's an odd number
Let n be 6 //00000110
N&1=0
00000110(6) & 00000001(1) =00000000 (0)
Thus it's an even number

C implementation

C实现

#include <stdio.h>
int main()
{
int n;
printf("enter no: ");
scanf("%d",&n);
//n&1 actually results in 0000000d where d is your LSB
if(n&1==1)
printf("it's odd no");//for odd no LSB 1
else
printf("it's even no");//for even no LSB 0
return 0;
}

Output

输出量

First run:
enter no: 7
it's odd no
Second run:
enter no: 6
it's even no

翻译自: https://www.includehelp.com/c-programs/find-odd-or-even-number-using-bitmasking.aspx

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