python 唯一元素

Here, we are implementing a python program to check whether all elements of a list are unique or not?

在这里，我们正在实现一个python程序来检查列表的所有元素是否唯一？

It's very simple to check, by following two steps

按照以下两个步骤进行检查非常简单

1. Convert the list in a set (as you should know that set contains the unique elements) – it will remove the duplicate elements if any.

   转换列表中的列表(您应该知道该集合包含唯一元素)–它将删除重复的元素(如果有)。

2. Then, compare the length of the list and set – if both are the same then all elements are unique.

   然后，比较列表和集合的长度–如果两者相同，则所有元素都是唯一的。

Program:

程序：

# function to check unique
def check_unique(x):
return len(x) == len(set(x))
# lists
x = [10, 20, 30, 40,50]
y = [10, 20, 20, 20, 20]
z = [10, 10, 10, 10, 10]
print("x: ", x)
print("len(x): ", len(x))
print("set(x): ", set(x))
print("len(set(x)): ", len(set(x)))
print("check_unique(x): ", check_unique(x))
print()
print("y: ", y)
print("len(y): ", len(y))
print("set(y): ", set(y))
print("len(set(y)): ", len(set(y)))
print("check_unique(y): ", check_unique(y))
print()
print("z: ", z)
print("len(z): ", len(z))
print("set(z): ", set(z))
print("len(set(z)): ", len(set(z)))
print("check_unique(z): ", check_unique(z))
print()

Output

输出量

x:  [10, 20, 30, 40, 50]
len(x):  5
set(x):  {40, 10, 50, 20, 30}
len(set(x)):  5
check_unique(x):  True
y:  [10, 20, 20, 20, 20]
len(y):  5
set(y):  {10, 20}
len(set(y)):  2
check_unique(y):  False
z:  [10, 10, 10, 10, 10]
len(z):  5
set(z):  {10}
len(set(z)):  1
check_unique(z):  False

翻译自: https://www.includehelp.com/python/check-all-elements-are-unique-or-not.aspx

python 唯一元素