Java Integer类numberOfLeadingZeros（）方法的示例

整数类numberOfLeadingZeros()方法 (Integer class numberOfLeadingZeros() method)

numberOfLeadingZeros() method is available in java.lang package.
在java.lang包中提供了numberOfLeadingZeros()方法 。
numberOfLeadingZeros() method is used to returns the number of 0's bits preceding the leftmost one bit in the 2's complement of the given parameter [value] of integer type. Otherwise, it returns 32 if the given parameter value is 0.
numberOfLeadingZeros()方法用于返回整数类型的给定参数[value]的2的补码中最左一位之前的0位数。否则，如果给定参数值为0，则返回32。
numberOfLeadingZeros() method is a static method, it is accessible with the class name too and if we try to access the method with the class object then also we will not get an error.
numberOfLeadingZeros()方法是一个静态方法，也可以使用类名进行访问，如果我们尝试使用类对象访问该方法，那么也不会出错。
numberOfLeadingZeros() method does not throw an exception.
numberOfLeadingZeros()方法不会引发异常。

Syntax:

句法：

    public static int numberOfLeadingZeros (int value);

Parameter(s):

参数：

int value – represents the integer value to be parsed.
int value –表示要解析的整数值。

Return value:

返回值：

The return type of this method is int, if the given argument is non-zero then, it returns the number of 0's bits preceding the leftmost one bit of the given int value. Else, if the given argument is zero then, it returns the value 32.

此方法的返回类型为int ，如果给定参数不为零，则它返回给定int值的最左一位之前的0位数。否则，如果给定参数为零，则返回值32。

Example:

例：

// Java program to demonstrate the example 
// of numberOfLeadingZeros (int value) method of Integer class
public class NumberOfLeadingZerosOfIntegerClass {
public static void main(String[] args) {
int value1 = 1296;
int value2 = 0;
// It returns the string representation of the given unsigned 
// integer value denoted by the argument in binary by calling
// Integer.toBinaryString(value1)
System.out.println("Integer.toBinaryString(value1): " + Integer.toBinaryString(value1));
// It returns the string representation of the given unsigned 
// integer value denoted by the argument in binary by calling
// Integer.toBinaryString(value2)
System.out.println("Integer.toBinaryString(value2): " + Integer.toBinaryString(value2));
// It returns the number of 0's bits preceding the leftmost side 
// one bit in the given argument 'value' by calling 
// Integer.numberOfLeadingZeros(value1)
System.out.println("Integer.numberOfLeadingZeros(value1): " + Integer.numberOfLeadingZeros(value1));
// It returns the value 32 because the value of 
// the given argument is zero 
System.out.println("Integer.numberOfLeadingZeros(value2): " + Integer.numberOfLeadingZeros(value2));
}
}

Output

输出量

Integer.toBinaryString(value1): 10100010000
Integer.toBinaryString(value2): 0
Integer.numberOfLeadingZeros(value1): 21
Integer.numberOfLeadingZeros(value2): 32