小程序 || 语句_C ++条件语句| 查找输出程序| 套装2

小程序 || 语句

Program 1:

程序1：

#include <iostream>
#include <stdio.h>
using namespace std;
int main()
{
int num = 0;
num = printf("%d ", printf("%d ", printf("ABC")));
if (num == 2) {
cout << "INDIA";
}
else if (num == 3) {
cout << "AUSTRALIA";
}
else {
cout << "CHINA";
}
return 0;
}

Output:

输出：

ABC3 2 INDIA

Explanation:

说明：

The above program will print "ABC3 2 INDIA" on the console screen.

上面的程序将在控制台屏幕上打印“ ABC3 2 INDIA” 。

The printf() function returns the total number of characters printed on the console screen.

printf()函数返回控制台屏幕上打印的字符总数。

Execution of the program step by step:

逐步执行程序：

num = printf("%d ",printf("%d ",printf("ABC")));

In this statement the innermost printf() will be executed first and prints "ABC" and returns 3, then the second printf() prints "3 " and returns 2 because 3 and space are two characters, and then the last outermost printf() will be executed and prints "2 " and returns 2 that is assigned to num variable.

在此语句中，最里面的printf()将首先执行并打印“ ABC”并返回3 ，然后第二个printf()打印“ 3”并返回2，因为3和空格是两个字符，然后是最后一个最外面的printf()将被执行并输出“2”，并返回2分配给num变量。

The num variable contains 2 then the first condition will be true and it will print "INDIA".

num变量包含2，那么第一个条件为true，它将输出“ INDIA” 。

Then the final output will be "ABC3 2 INDIA".

然后，最终输出将为“ ABC3 2 INDIA” 。

Program 2:

程式2：

#include <iostream>
#include <stdio.h>
using namespace std;
int main()
{
int num = 0;
if (EOF) {
cout << "INDIA";
}
else if (NULL) {
cout << "AUSTRALIA";
}
else {
cout << "USA";
}
return 0;
}

Output:

输出：

INDIA

Explanation:

说明：

The above program will print "INDIA" on the console screen. Because the value of the EOF macro is -1. And any non-zero value is considered as a true for if conditions, this, the first condition will be true and it will print "INDIA" on the console screen.

上面的程序将在控制台屏幕上打印“ INDIA” 。因为EOF宏的值为-1 。如果条件为条件，则任何非零值都将被视为true，则第一个条件将为true，并将在控制台屏幕上显示“ INDIA” 。