我在我的一个实时网络应用程序中遇到了这个问题.看来如果你通过PHP PDO向MysqL发出一个多语句查询,并且第一个语句是一个insert语句,而第二个语句是一个update语句,那么PDO :: nextRowset()函数不会返回正确的数字结果集(请注意,自PHP 5.3起,PDO应该支持每个MySQL查询的多个语句.)
这是一个例子：
create database `test`character set utf8 collate utf8_general_ci;
create table `test`.`testtable`( `id` int );
PHP
$link = new \PDO('MysqL:host=localhost;dbname=test','username','password');
//Run one of the 4 $handle assignments at a time (comment out all but one).
//Run #4 on an empty table to compare the results of #1 and #4.
//WORKS: INSERT,followed by SELECT,followed UPDATE
//Output:
//Rowset 1
//Rowset 2
//Results detected
$handle = $link->prepare(' insert into testtable(id) values(1);
select * from testtable where id = ?;
update testtable set id = 2 where id = ?;');
//WORKS: SELECT,followed by UPDATE
//Output:
//Rowset 1
//Results detected
$handle = $link->prepare('select * from testtable where id = ?;
update testtable set id = 2 where id = ?;');
//WORKS: UPDATE,followed by SELECT
//Output:
//Rowset 1
//Rowset 2
//Results detected
$handle = $link->prepare('select * from testtable where id = ?;
update testtable set id = 2 where id = ?;');
//DOESN'T WORK: INSERT,followed by UPDATE,followed by SELECT
//Output:
//Rowset 1
//Expected output: same as examples 1 and 3
$handle = $link->prepare('insert into testtable(id) values(1);
update testtable set id = 2 where id = ?;
select * from testtable where id = ?;');
$handle->bindValue('1','1');
$handle->bindValue('2','2');
$handle->execute();
$i = 1;
do{
print('Rowset ' . $i++ . "\n");
if($handle->columnCount() > 0)
print("Results detected\n");
}while($handle->nextRowset());
?>
有没有人知道我做错了什么？为什么我不能把我的选择声明放在最后？
PHP 5.3.5
MysqL 5.1.54
)
