C#通过SSH连接MySql

　　出于安全考虑，有的时候数据库服务器只能通过SSH访问，比如MySql服务装在了服务器A上，并且A机器只允许B机器才能访问，而部署环境可能在C机器上，这时候就要C服务器通过B服务器连接A服务器，这时候就需要用到SSH方式连接，需要SSH.NET类库：

下载地址：https://github.com/sshnet/SSH.NET

　　代码如下：

using MySql.Data.MySqlClient;
using Renci.SshNet;
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;namespace SSHMySql
{public partial class Form1 : Form{public Form1(){InitializeComponent();SSHConnectMySql();}public void SSHConnectMySql(){string SSHHost = "*.*.*.*";        // SSH地址int SSHPort = 22;              // SSH端口string SSHUser = "user";           // SSH用户名string SSHPassword = "pwd";           // SSH密码string sqlIPA = "127.0.0.1";// 映射地址  实际上也可以写其它的   Linux上的MySql的my.cnf bind-address 可以设成0.0.0.0 或者不设置string sqlHost = "192.168.1.20"; // mysql安装的机器IP 也可以是内网IP 比如：192.168.1.20uint sqlport = 3306;        // 数据库端口及映射端口string sqlConn = "Database=mysql;Data Source=" + sqlIPA + ";Port=" + sqlport + ";User Id=user;Password=pwd;CharSet=utf8";string sqlSELECT = "select * from user";PasswordConnectionInfo connectionInfo = new PasswordConnectionInfo(SSHHost, SSHPort, SSHUser, SSHPassword);connectionInfo.Timeout = TimeSpan.FromSeconds(30);using (var client = new SshClient(connectionInfo)){try{client.Connect();if (!client.IsConnected){MessageBox.Show("SSH connect failed");}var portFwdL = new ForwardedPortLocal(sqlIPA, sqlport, sqlHost, sqlport); //映射到本地端口
                    client.AddForwardedPort(portFwdL);portFwdL.Start();if (!client.IsConnected){MessageBox.Show("port forwarding failed");}MySqlConnection conn = new MySqlConnection(sqlConn);MySqlDataAdapter myDataAdapter = new MySqlDataAdapter();myDataAdapter.SelectCommand = new MySqlCommand(sqlSELECT, conn);try{conn.Open();DataSet ds = new DataSet();myDataAdapter.Fill(ds);dataGridView1.DataSource = ds.Tables[0];}catch (Exception ee){MessageBox.Show(ee.Message);}finally{conn.Close();}client.Disconnect();}catch (Exception ex){MessageBox.Show(ex.Message);}}}}
}