请你实现一个类 SubrectangleQueries ，它的构造函数的参数是一个 rows x cols 的矩形（这里用整数矩阵表示），并支持以下两种操作：

1. updateSubrectangle(int row1, int col1, int row2, int col2, int newValue)

用 newValue 更新以 (row1,col1) 为左上角且以 (row2,col2) 为右下角的子矩形。
2. getValue(int row, int col)

返回矩形中坐标 (row,col) 的当前值。

代码

    class SubrectangleQueries {int[][] rect;public SubrectangleQueries(int[][] rectangle) {rect=rectangle;}public void updateSubrectangle(int row1, int col1, int row2, int col2, int newValue) {for(int i=row1;i<=row2;i++)for(int j=col1;j<=col2;j++)rect[i][j]=newValue;}public int getValue(int row, int col) {return rect[row][col];}}/*** Your SubrectangleQueries object will be instantiated and called as such:* SubrectangleQueries obj = new SubrectangleQueries(rectangle);* obj.updateSubrectangle(row1,col1,row2,col2,newValue);* int param_2 = obj.getValue(row,col);*/