c++语句switch语句_错误：案例标签不在C中的switch语句内

c++语句switch语句

The error: case label not within a switch statement occurs in C language with switch case statement, when switch (variable/value) statement is terminated by the semicolon (;).

错误：当switch(变量/值)语句由分号( ; )终止时，C语言中的case标签使用switch case语句以C语言出现。

Example:

例：

#include <stdio.h>
int main(void) {
int choice = 2;
switch(choice);
{
case 1:
printf("Case 1\n");
break;
case 2:
printf("Case 2\n");
break;	    
case 3:
printf("Case 3\n");
break;	    
case 4:
printf("Case 4\n");
break;	    
default:
printf("Case default\n");
}
return 0;
}

Output

输出量

prog.c: In function ‘main’:
prog.c:9:6: error: case label not within a switch statement
case 1:
^~~~
prog.c:11:10: error: break statement not within loop or switch
break;
^~~~~
prog.c:12:6: error: case label not within a switch statement
case 2:
^~~~
prog.c:14:10: error: break statement not within loop or switch
break;
^~~~~
prog.c:15:6: error: case label not within a switch statement
case 3:
^~~~
prog.c:17:10: error: break statement not within loop or switch
break;
^~~~~
prog.c:18:6: error: case label not within a switch statement
case 4:
^~~~
prog.c:20:10: error: break statement not within loop or switch
break;
^~~~~
prog.c:21:6: error: ‘default’ label not within a switch statement
default:
^~~~~~~

How to fix?

怎么修？

See the statement switch(choice); it is terminated by semicolon (;) – it must not be terminated. To fix this error, remove semicolon after this statement.

参见语句switch(choice); 它以分号( ; )终止–一定不能终止。要解决此错误，请在此语句后删除分号。

Correct code:

正确的代码：

#include <stdio.h>
int main(void) {
int choice = 2;
switch(choice)
{
case 1:
printf("Case 1\n");
break;
case 2:
printf("Case 2\n");
break;	    
case 3:
printf("Case 3\n");
break;	    
case 4:
printf("Case 4\n");
break;	    
default:
printf("Case default\n");
}
return 0;
}

Output

输出量