strictmath_Java StrictMath sqrt（）方法与示例

strictmath

StrictMath类sqrt()方法 (StrictMath Class sqrt() method)

sqrt() Method is available in java.lang package.
sqrt()方法在java.lang包中可用。
sqrt() Method is used to find the square root of the given parameter in the method. Here, "sqrt" stands for square root
sqrt() Method is a static method so it is accessible with the class name and if we try to access the method with the class object then we will not get any error.
sqrt() Method does not throw any exception at the time of finding the square root of the given number.
sqrt()方法用于查找方法中给定参数的平方根。在这里， “ sqrt”代表平方根
sqrt()方法是静态方法，因此可以使用类名进行访问，如果尝试使用类对象访问该方法，则不会收到任何错误。
sqrt()方法在查找给定数字的平方根时不会引发任何异常。

Syntax:

句法：

    public static double sqrt(double d);

Parameter(s):

参数：

double d – represents for which we have to find the square root.
double d –代表我们必须找到其平方根。

Return value:

返回值：

The return type of the method is double, it returns the square root of the given parameter.

该方法的返回类型为double ，它返回给定参数的平方根。

Note:

注意：

If we pass NaN, the method returns the same (i.e. NaN).
如果我们通过NaN，则该方法返回相同的值(即NaN)。
If we pass zero, the method returns the same value with the same sign.
如果传递零，则该方法返回具有相同符号的相同值。
If we pass an argument positive infinity, the method returns the same.
如果我们传递参数正无穷大，则该方法将返回相同的结果。

Example:

例：

// Java program to demonstrate the example of sqrt(double d) 
// method of StrictMath class.
public class Sqrt {
public static void main(String[] args) {
// variable declarations
double d1 = -0.0;
double d2 = 0.0;
double d3 = -7.0 / 0.0;
double d4 = 7.0 / 0.0;
double d5 = 1000.0;
double d6 = -1000.0;
// Display previous value of d1,d2,d3,d4,d5 and d6
System.out.println("d1: " + d1);
System.out.println("d2: " + d2);
System.out.println("d3: " + d3);
System.out.println("d4: " + d4);
System.out.println("d5: " + d5);
System.out.println("d6: " + d6);
/*Here , we will get (-0.0) because we are passing parameter (-0.0) */
System.out.println("StrictMath.sqrt(d1): " + StrictMath.sqrt(d1));
// Here , we will get (0.0) because we are passing parameter 
// (0.0) so the square root is the same
System.out.println("StrictMath.sqrt(d2): " + StrictMath.sqrt(d2));
// Here , we will get (NaN) because we are passing parameter 
// (-7.0/0.0) so the square root is (-Infinity)
System.out.println("StrictMath.sqrt(d3): " + StrictMath.sqrt(d3));
// Here , we will get (Infinity) because we are passing 
// parameter (7.0/0.0) so the square root is (Infinity)
System.out.println("StrictMath.sqrt(d4): " + StrictMath.sqrt(d4));
// Here , we will get (square root of given argument) because 
// we are passing parameter (1000.0) 
System.out.println("StrictMath.sqrt(d5): " + StrictMath.sqrt(d5));
// Here , we will get (NaN) because we are passing parameter 
// (-1000.0) 
System.out.println("StrictMath.sqrt(d6): " + StrictMath.sqrt(d6));
}
}

Output

输出量

d1: -0.0
d2: 0.0
d3: -Infinity
d4: Infinity
d5: 1000.0
d6: -1000.0
StrictMath.sqrt(d1): -0.0
StrictMath.sqrt(d2): 0.0
StrictMath.sqrt(d3): NaN
StrictMath.sqrt(d4): Infinity
StrictMath.sqrt(d5): 31.622776601683793
StrictMath.sqrt(d6): NaN