前言
这次那了一个和fuW并列的第一,然而似乎都不是很难。(因为第1题有bug所以满分不了)
成绩
只放Rank 1∼10Rank1∼10
RankRank | PersonPerson | ScoreScore |
---|---|---|
11 | 193193 | |
11 | 193193 | |
33 | 136136 | |
44 | 129129 | |
55 | 101101 | |
66 | 8686 | |
77 | 8484 | |
88 | 7979 | |
88 | 7979 | |
1010 | 2015yjy2015yjy | 5555 |
正题
T1:nssl1148,jzoj5461−T1:nssl1148,jzoj5461−购物【可撤回贪心,,堆】
博客链接:https://blog.csdn.net/Mr_wuyongcong/article/details/82713862
拆网线【贪心】
博客链接:https://blog.csdn.net/Mr_wuyongcong/article/details/82714314
nssl1150,jzoj5309−nssl1150,jzoj5309−密室【分层建图,SPFA,SPFA】
博客链接:https://blog.csdn.net/Mr_wuyongcong/article/details/82714434
一些codecode
一些code
T1 93(AC)代码
#include<cstdio>
#include<algorithm>
#define N 50010
using namespace std;
struct node{long long w,sct,num;
}a[2*N];
long long n,k,m,p,q,ans;
bool v[N];
bool cmp(node x,node y)
{return x.w<y.w;}
int main()
{scanf("%lld%lld%lld",&n,&k,&m);for(long long i=1;i<=n;i++){scanf("%lld%lld",&p,&q);a[i]=(node){p,0,i};a[i+n]=(node){q,1,i};}sort(a+1,a+1+2*n,cmp);for(long long i=1;i<=2*n;i++){if(m>=a[i].w&&!v[a[i].num]&&(!a[i].sct||k)){ans++;m-=a[i].w;v[a[i].num]=true;if(a[i].sct) k--;}}printf("%lld",ans);
}
T2 5分代码
#include<cstdio>
#include<cstring>
#include<algorithm>
#define N 100010
using namespace std;
struct node{int to,next;
}a[N*2];
int ls[N],t,n,k,x,f[N][2],tot;
void addl(int x,int y)
{a[++tot].to=y;a[tot].next=ls[x];ls[x]=tot;a[++tot].to=x;a[tot].next=ls[y];ls[y]=tot;
}
void dp(int x,int fa)
{int mark=0;for(int i=ls[x];i;i=a[i].next){int y=a[i].to;if(y==fa) continue;dp(y,x);f[x][1]+=f[y][0];if(f[y][1]-f[y][0]>f[mark][1]-f[mark][0]) mark=y;}f[x][0]=f[x][1]+f[mark][1]-f[mark][0];f[x][1]++;
}
int main()
{scanf("%d",&t);for(int ti=1;ti<=t;ti++){memset(f,0,sizeof(f));memset(ls,0,sizeof(ls));scanf("%d%d",&n,&k);tot=0;for(int i=1;i<n;i++){scanf("%d",&x);addl(i+1,x);}dp(1,0);int ans=f[1][0];if(ans*2>=k) printf("%d\n",(k+1)/2);else printf("%d",ans+(k-ans*2));}
}
T3 95分代码
#include<cstdio>
#include<deque>
#define p(x,y) x*n+y
#define N 5010
#define M 6010
#define MS 1024
using namespace std;
struct node{int to,next;bool w;
}a[MS*(N+M)];
int n,m,k,x,y,w,MAX_State,d[N*MS],tot,ls[N*MS];
deque<int> q;
void addl(int x,int y,int w)
{a[++tot].to=y;a[tot].next=ls[x];a[tot].w=w;ls[x]=tot;
}
void bfs()
{q.push_back(p(0,1));d[p(0,1)]=1;while(!q.empty()){int x=q.front();q.pop_front();for(int i=ls[x];i;i=a[i].next){int y=a[i].to;//if(y%n==0)// printf("%d\n",y);if(!d[y]){d[y]=d[x]+a[i].w;if(a[i].w==0) q.push_front(y);else q.push_back(y); }}}
}
int main()
{scanf("%d%d%d",&n,&m,&k);MAX_State=1<<k;for(int i=1;i<=n;i++)for(int j=1;j<=k;j++){scanf("%d",&x);if(x){for(int state=0;state<MAX_State;state++)if(!(state&(1<<(j-1))))addl(p(state,i),p((state|(1<<(j-1))),i),0);}}for(int i=1;i<=m;i++){int state=0;scanf("%d%d",&x,&y);for(int i=1;i<=k;i++){scanf("%d",&w);state+=w<<(i-1);}for(int j=0;j<MAX_State;j++)if((j&state)==state)addl(p(j,x),p(j,y),1);}bfs();int ans;ans=2147483647;for(int j=0;j<MAX_State;j++)if(d[p(j,n)])ans=min(ans,d[p(j,n)]);if(ans==2147483647) printf("No Solution");else printf("%d",ans-1);
}
尾声
依旧没了