js 传值到 PHP 问题
说一下我的需求：通过点击button的时候，去通过php查找指定日期的数据库当中的数据，
function load_point(date) {
// Change this depending on the name of your PHP file
downloadUrl("phpsqlajax_genxml2.php", function(data) {
//alert("downloadUrl1");
var xml = data.responseXML;
var markers = xml.documentElement.getElementsByTagName("marker");
var polyOptions = {
strokeColor: '#000000', // 颜色
strokeOpacity: 1.0, // 透明度
strokeWeight: 2 // 宽度
}
var poly = new google.maps.Polyline(polyOptions);
poly.setMap(map); // 装载
//alert("downloadUrl2");
for (var i = 0; i
var name = markers[i].getAttribute("name");
var address = markers[i].getAttribute("address");
var type = markers[i].getAttribute("type");
var point = new google.maps.LatLng(
parseFloat(markers[i].getAttribute("lat")),
parseFloat(markers[i].getAttribute("lng")));
var html = "" + name + "
" + address;
//var icon = customIcons[type] || {};
var path = poly.getPath(); //获取线条的坐标
path.push(point); //为线条添加标记坐标
//生成标记图标
var marker = new google.maps.Marker({
position:point
// map: map,
//icon: "http://labs.google.com/ridefinder/images/mm_20_green.png"
});
}
});
}
function downloadUrl(url, callback) {
var request = window.ActiveXObject ?
new ActiveXObject('Microsoft.XMLHTTP') :
new XMLHttpRequest;
request.onreadystatechange = function() {
if (request.readyState == 4) {
request.onreadystatechange = doNothing;
callback(request, request.status);
}
};
request.open('GET', url, true);
request.send(null);
}
下面是phpsqlajax_genxml2.php
$username="root";
$password="";
$database="data";
function parseToXML($htmlStr)
{
$xmlStr=str_replace('
$xmlStr=str_replace('>','>',$xmlStr);
$xmlStr=str_replace('"','"',$xmlStr);
$xmlStr=str_replace("'",''',$xmlStr);
$xmlStr=str_replace("&",'&',$xmlStr);
return $xmlStr;
}
// Opens a connection to a MySQL server
$connection=mysql_connect ('localhost', $username, $password);
if (!$connection) {
die('Not connected : ' . mysql_error());
}
// Set the active MySQL database
$db_selected = mysql_select_db($database, $connection);
if (!$db_selected) {
die ('Can\'t use db : ' . mysql_error());
}
// Select all the rows in the markers table
$query = "SELECT * FROM markers WHERE 1";
$result = mysql_query($query);
if (!$result) {
die('Invalid query: ' . mysql_error());
}
header("Content-type: text/xml");
// Start XML file, echo parent node
echo '';
// Iterate through the rows, printing XML nodes for each
while ($row = @mysql_fetch_assoc($result)){
// ADD TO XML DOCUMENT NODE
echo '
echo 'name="' . parseToXML($row['name']) . '" ';
echo 'address="' . parseToXML($row['address']) . '" ';
echo 'lat="' . $row['lat'] . '" ';
echo 'lng="' . $row['lng'] . '" ';
echo 'type="' . $row['type'] . '" ';
echo '/>';
}
// End XML file
echo '';
?>
现在想怎么能把date值传递到phpsqlajax_genxml.php
------解决思路----------------------
downloadUrl("phpsqlajax_genxml2.php?date="+new Date-0, function(data) {
....
后面加一个当前时间刻度的参数
php 访问 这个 $GET['date'] 就可以了
