1.定义结构体数组存储5个学生的信息：姓名，年龄，性别
定义函数实现输入，要求形参使用结构体指针接收
函数实现5个学生年龄排序(注意对年龄排序时，交换的是所有信息)
定义函数实现输出，要求形参使用结构体指针接收
#include <string.h>
#include <stdlib.h>
#include <stdio.h>struct student
{char name[20];int age;char gender; //f,m};void input(int n, struct student *p);
void sort_by_age(int n, struct student *p );
void ouput(int n, struct student *p);int main(int argc, const char *argv[])
{int n=5;struct student arr_stu[n];struct student *p = arr_stu;input(n, arr_stu);printf("before sort:\n");ouput(n, arr_stu);putchar(10);sort_by_age(n, arr_stu);printf("after sort:\n");ouput(n, arr_stu);return 0;
}void input(int n, struct student *p){for(int i=0; i<n ;i++){printf("please input no.[%d] student's info:\n", i+1);printf("name:");scanf("%s", (p+i)->name);printf("age:");scanf("%d", &(p+i)->age);printf("gender:");scanf(" %c", &(p+i)->gender);}
}
void sort_by_age(int n, struct student *p )
{int descend=0;for(int i=0; i<n-1; i++){int cur=i;for(int j=i+1; j<n; j++){if(descend==1 && (p+cur)->age < (p+j)->age){cur=j;}else if(descend==0 && (p+cur)->age > (p+j)->age){cur=j;}}if(cur!=i){struct student t;strcpy(t.name, (p+cur)->name);t.age = (p+cur)->age;t.gender = (p+cur)->gender;strcpy((p+cur)->name, (p+i)->name);(p+cur)->age = (p+i)->age;(p+cur)->gender = (p+i)->gender;strcpy((p+i)->name, t.name);(p+i)->age = t.age;(p+i)->gender = t.gender;}}}
void ouput(int n, struct student *p)
{printf("name\tage\tgender\n");for(int i=0; i<n; i++){printf("%s\t%d\t%c\n", (p+i)->name, (p+i)->age, (p+i)->gender);} putchar(10);}
~
~
~
~ 输出结果:
please input no.[1] student's info:
name:a
age:19
gender:f
please input no.[2] student's info:
name:b
age:29
gender:m
please input no.[3] student's info:
name:c
age:27
gender:f
please input no.[4] student's info:
name:d
age:18
gender:m
please input no.[5] student's info:
name:e
age:23
gender:f
before sort:
name age gender
a 19 f
b 29 m
c 27 f
d 18 m
e 23 fafter sort:
name age gender
d 18 m
a 19 f
e 23 f
c 27 f
b 29 m
2.定义车辆a和车辆b，实现交换
车的信息：品牌，单价，颜色
#include <string.h>
#include <stdlib.h>
#include <stdio.h>struct car
{char brand[20];int price;char color[10];
};void output(struct car ca);int main(int argc, const char *argv[])
{struct car a;struct car b;strcpy(a.brand, "Tesla");a.price = 20;strcpy(a.color, "black");printf("car a:\n");output(a);strcpy(b.brand, "byd");b.price =30;strcpy(b.color, "blue");printf("car b:\n");output(b);//exchangestruct car t;strcpy(t.brand, a.brand);strcpy(a.brand, b.brand);strcpy(b.brand, t.brand);t.price = a.price;a.price = b.price;b.price = t.price;strcpy(t.color, a.color); strcpy(a.color, b.color);strcpy(b.color, t.color);printf("car a:\n");output(a);printf("car b:\n");output(b);return 0;
}void output(struct car ca)
{printf("brand\tprice\tcolor\n");printf("%s\t%d\t%s\n\n", ca.brand, ca.price, ca.color);}
~ 输出结果
car a:
brand price color
Tesla 20 blackcar b:
brand price color
byd 30 bluecar a:
brand price color
byd 30 bluecar b:
brand price color
Tesla 20 black
3.思维导图
