问题： scala中对象转json字符串报错

提示：scala中get和set方法实现与java中的不一样。

Error:(26, 10) ambiguous reference to overloaded definition,
both method toJSONString in class JSON of type (x$1: Any, x$2: com.alibaba.fastjson.serializer.SerializerFeature*)String
and  method toJSONString in class JSON of type (x$1: Any)String
match argument types (com.yupaopao.platform.common.dto.Response[com.yupaopao.platform.common.dto.PageResult[com.yupaopao.platform.rank.api.response.TopsRankDTO]]) and expected result type StringJSON.toJSONString(accompany_rank)

一、使用fastjson或者json4s

<dependency><groupId>com.alibaba</groupId><artifactId>fastjson</artifactId><version>2.0.23</version>
</dependency><dependency><groupId>org.json4s</groupId><artifactId>json4s-jackson_${scala.version}</artifactId><version>3.2.11</version>
</dependency>

1、使用fastjson

import com.alibaba.fastjson.JSON
import com.alibaba.fastjson.serializer.{SerializeConfig, SerializerFeature}case class Person(id: Integer, name: String, item: String)
object test {def main(args: Array[String]): Unit = {val od = Order(1,"01",null)val jsonString = JSON.toJSONString(od, new SerializeConfig(true),SerializerFeature.WriteMapNullValue)println(jsonString)    #结果：{"id":1,"name":"01","item":null}val obj = JSON.parseObject(jsonString, classOf[Person])println(obj)          #结果：Person(1,01,null)}
}

补充：scala case class + BeanProperty+fastjson

2、使用json4s

import org.json4s._
import org.json4s.jackson.{JsonMethods, Serialization}case class Person(id: Int, name: String, item: String)
object test {def main(args: Array[String]): Unit = {#隐式转换implicit val formats = Serialization.formats(NoTypeHints)#对象转jsonStringval od = Person(1,"01",null)val jsonString = Serialization.write(od)println(jsonString)    #结果：{"id":1,"name":"01","item":null}#jsonString转对象val person = JsonMethods.parse(jsonString).extract[Person]println(person)        #结果：Person(1,01,null)  }
}