文章目录
- 原始需求
- 分析
- 实施步骤
- 引入依赖
- 核心编码
- 运行效果
原始需求
有网友提问: 我想在程序中动态地向同一个jar包中添加文件,比如,我的可执行jar包是test.jar,我要在它运行时生成一些xml文件并将这些文件添加到test.jar中,请问如何实现?
分析
test.jar在运行过程中是无法改变自身内容的,但是可以创建内容与test.jar一致的test2.jar
问题就转换成了:
- 如何复制已有的test.jar重命名为test2.jar
- 如何继续向test2.jar添加新的文件
实施步骤
引入依赖
<dependency><groupId>org.apache.commons</groupId><artifactId>commons-lang3</artifactId><version>3.12.0</version></dependency><dependency><groupId>commons-io</groupId><artifactId>commons-io</artifactId><version>2.5</version></dependency><dependency><groupId>org.apache.commons</groupId><artifactId>commons-compress</artifactId><version>1.23.0</version></dependency>
核心编码
借助 commons-compress 来操作Jar
public void test()throws IOException{String src = getClass().getResource("/apache-jstl.jar").getPath();String add1 = getClass().getResource("/servlet-api.jar").getPath();String add2 = getClass().getResource("/log4j2.xml").getPath();String newJar = src.replace(".jar", DateFormatUtils.format(System.currentTimeMillis(), "_HHmmssSSS") + ".jar");log.info("源文件: {}", src);log.info("++新增: {}", add1);log.info("++新增: {}", add2);log.info("新文件: {}", newJar);try (ArchiveOutputStream outputStream = new JarArchiveOutputStream(new FileOutputStream(newJar));JarArchiveInputStream jarInput = new JarArchiveInputStream(new FileInputStream(src))){JarArchiveEntry jarEntry;while ((jarEntry = jarInput.getNextJarEntry()) != null){if (!jarEntry.isDirectory()){outputStream.putArchiveEntry(jarEntry);IOUtils.copy(jarInput, outputStream);}}outputStream.flush();// 追加addFilesFile[] addFiles = {new File(add1), new File(add2)};for (File addFile : addFiles){JarArchiveEntry addEntry = new JarArchiveEntry("add/" + addFile.getName());outputStream.putArchiveEntry(addEntry);try (InputStream entryInputStream = new FileInputStream(addFile)){IOUtils.copy(entryInputStream, outputStream);}}// 追加add/001.txtJarArchiveEntry entry = new JarArchiveEntry("add/001.txt");outputStream.putArchiveEntry(entry);outputStream.write("org.apache.commons.compress.archivers.jar.JarArchiveOutputStream;".getBytes(StandardCharsets.UTF_8));outputStream.closeArchiveEntry();outputStream.finish();}}
使用JDK API实现
public void test2(){try{String src = getClass().getResource("/apache-jstl.jar").getPath();String add1 = getClass().getResource("/servlet-api.jar").getPath();String add2 = getClass().getResource("/log4j2.xml").getPath();String newJar = src.replace(".jar", DateFormatUtils.format(System.currentTimeMillis(), "_HHmmssSSS") + ".jar");log.info("源文件: {}", src);log.info("++新增: {}", add1);log.info("++新增: {}", add2);log.info("新文件: {}", newJar);addFilesToJar(new File(src), newJar, new File(add1), new File(add2));}catch (IOException e){log.error(e.getMessage(), e);}}/*** JDK-API实现-将addFiles添加到srcJar并重命名为newJar* * @param srcJar* @param newJar* @param addFiles* @throws IOException*/private void addFilesToJar(File srcJar, String newJar, File... addFiles)throws IOException{try (JarOutputStream jarOutputStream = new JarOutputStream(new FileOutputStream(newJar)); JarFile jarFile = new JarFile(srcJar)){// 遍历jar文件数据写入新jarEnumeration<JarEntry> entrys = jarFile.entries();while (entrys.hasMoreElements()){JarEntry jarEntry = entrys.nextElement();if (!jarEntry.isDirectory()){jarOutputStream.putNextEntry(jarEntry);try (InputStream entryInputStream = jarFile.getInputStream(jarEntry)){IOUtils.copy(entryInputStream, jarOutputStream);}}}// 追加写入for (File addFile : addFiles){JarEntry jarEntry = new JarEntry("add/" + addFile.getName());jarOutputStream.putNextEntry(jarEntry);try (InputStream entryInputStream = new FileInputStream(addFile)){IOUtils.copy(entryInputStream, jarOutputStream);}}}}
运行效果
原始文件
运行后:
大功告成!!!
有任何问题和建议,都可以向我提问讨论,大家一起进步,谢谢!
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