AcWing 794. 高精度除法
题目描述
给定两个非负整数（不含前导 0） A，B，请你计算 A/B 的商和余数。
输入格式
共两行，第一行包含整数 A，第二行包含整数 B。
输出格式
共两行，第一行输出所求的商，第二行输出所求余数。
数据范围
1≤A 的长度≤100000,
1≤B≤10000,
B 一定不为 0
输入样例：
7
2
输出样例：
3
1
C++
#include <iostream>
#include <string>using namespace std;string div(string &a, int b, int &carry) {carry = 0;string result;for (size_t i = 0; i < a.size(); ++i) {carry = a[i] - '0' + carry * 10;result.push_back(carry / b + '0');carry %= b;}while (result.size() > 1 && result[0] == '0') result.erase(0, 1);return result;
}int main() {string a;int b, carry;cin >> a >> b;cout << div(a, b, carry) << endl;cout << carry << endl;return 0;
}
#include <iostream>
#include <vector>
#include <algorithm>using namespace std;vector<int> div(vector<int> &A, int b, int &r)
{vector<int> C;r = 0;for (int i = A.size() - 1; i >= 0; i -- ){r = r * 10 + A[i];C.push_back(r / b);r %= b;}reverse(C.begin(), C.end());while (C.size() > 1 && C.back() == 0) C.pop_back();return C;
}int main()
{string a;vector<int> A;int B;cin >> a >> B;for (int i = a.size() - 1; i >= 0; i -- ) A.push_back(a[i] - '0');int r;auto C = div(A, B, r);for (int i = C.size() - 1; i >= 0; i -- ) cout << C[i];cout << endl << r << endl;return 0;
}
Go
package mainimport ("fmt""strings"
)func div(a string, b int) (string, int) {carry := 0var result strings.Builderfor i := 0; i < len(a); i++ {carry = carry*10 + int(a[i]-'0')result.WriteByte(uint8(carry/b) + '0')carry %= b}resStr := result.String()for len(resStr) > 1 && resStr[0] == '0' {resStr = resStr[1:]}return resStr, carry
}func main() {var a stringvar b intfmt.Scanln(&a)fmt.Scanln(&b)res, carry := div(a, b)fmt.Println(res)fmt.Println(carry)
}
)
