接上一篇
连接查询
连接查询也中多表查询,常用于查询来自于多张表的数据,通过不同的连接方式把多张表组成一张新的临时表,再对临时表做数据处理。
#表基础信息,内容可从上一篇博客中查看
mysql> desc departments;
+-----------+-------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-----------+-------------+------+-----+---------+----------------+
| dept_id | int | NO | PRI | NULL | auto_increment |
| dept_name | varchar(10) | YES | | NULL | |
+-----------+-------------+------+-----+---------+----------------+
2 rows in set (0.00 sec)mysql> desc employees;
+--------------+-------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+--------------+-------------+------+-----+---------+----------------+
| employee_id | int | NO | PRI | NULL | auto_increment |
| name | varchar(10) | YES | | NULL | |
| hire_date | date | YES | | NULL | |
| birth_date | date | YES | | NULL | |
| email | varchar(25) | YES | | NULL | |
| phone_number | char(11) | YES | | NULL | |
| dept_id | int | YES | MUL | NULL | |
+--------------+-------------+------+-----+---------+----------------+
7 rows in set (0.00 sec)mysql> desc salary;
+-------------+------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------------+------+------+-----+---------+----------------+
| id | int | NO | PRI | NULL | auto_increment |
| date | date | YES | | NULL | |
| employee_id | int | YES | MUL | NULL | |
| basic | int | YES | | NULL | |
| bonus | int | YES | | NULL | |
+-------------+------+------+-----+---------+----------------+
5 rows in set (0.00 sec)
内连接
#1.等值连接查询
#1)查询每个员工所在的部门名
mysql> select emp.name,dep.dept_name from employees emp,departments dep where emp.dept_id=dep.dept_id;
或
mysql> select emp.name,dep.dept_name from employees emp join departments dep on emp.dept_id=dep.dept_id;
#2) 查询员工编号8的员工所有部门的部门名称
mysql> select emp.name,dep.dept_name from employees emp,departments dep where emp.dept_id=dep.dept_id and emp.employee_id=8;
或
mysql> select emp.name,dep.dept_name from employees emp join departments dep on emp.dept_id=dep.dept_id and emp.employee_id=8;
#3)查询每个员工所有信息及所有部门名称
mysql> select emp.*,dep.dept_name from employees emp,departments dep where emp.dept_id=dep.dept_id;
或
mysql> select emp.*,dep.dept_name from employees emp join departments dep on emp.dept_id=dep.dept_id;
#4)查询每个员工姓名、部门编号、部门名称
mysql> select emp.name,dep.dept_id,dep.dept_name from employees emp,departments dep where emp.dept_id=dep.dept_id;
或
mysql> select emp.name,dep.dept_id,dep.dept_name from employees emp join departments dep on emp.dept_id=dep.dept_id;
#5)查询11号员工的名字及2018年每个月总工资
mysql> select emp.name,(sal.basic+sal.bonus) as 总工资 from employees emp join salary sal on emp.employee_id=sal.employee_id where emp.employee_id=11 and year(date)=2018;
#6) 查询每个员工2018年的总工资
mysql> select emp.name,sum(sal.basic+sal.bonus) as 总工资 from employees emp join salary sal on emp.employee_id=sal.employee_id where year(date)=2018 group by name;
#7) 查询每个员工2018年的总工资,按总工资升序排列
mysql> select emp.name,sum(sal.basic+sal.bonus) as 总工资 from employees emp join salary sal on emp.employee_id=sal.employee_id where year(date)=2018 group by name order by 总工资;
#8) 查询2018年总工资大于30万的员工,按2018年总工资降序排列
mysql> select emp.name,sum(sal.basic+sal.bonus) as 总工资 from employees emp join salary sal on emp.employee_id=sal.employee_id where year(date)=2018 group by name having 总工资>300000 order by 总工资 desc;
#2.非等值连接查询
mysql> create table wage_grade(id int primary key auto_increment,grade char(1),low int,high int);
Query OK, 0 rows affected (0.85 sec)mysql> insert into wage_grade(grade,low,high)values('A',5000,8000),('B', 8001, 10000),('C', 10001, 15000),-> ('D', 15001, 20000),('E', 20001, 1000000);
Query OK, 5 rows affected (0.08 sec)
Records: 5 Duplicates: 0 Warnings: 0
#1)查询2018年12月员工基本工资级别
mysql> select employee_id,date,basic,grade from salary as s inner join wage_grade as g on s.basic between g.low and g.high where year(date)=2018 and month(date)=12;
#2)查询2018年12月员工各基本工资级别的人数
mysql> select grade,count(grade) from salary as s inner join wage_grade as g on s.basic between g.low and g.high where year(date)=2018 and month(date)=12 group by grade;
#3)查询2018年12月员工基本工资级别,员工需要显示姓名
mysql> select emp.name,date,basic,grade from salary as s inner join wage_grade as g inner join employees emp on s.basic between g.low and g.high where year(date)=2018 and month(date)=12 and emp.employee_id=s.employee_id;
外连接
mysql> insert into departments(dept_name) values("小卖部"),("行政部"),("公关部");
#1. 左连接查询
#1)输出没有员工的部门名
mysql> select dept_name,emp.name from departments as dep left join employees emp on emp.dept_id=dep.dept_id where emp.name is null;
#2. 右连接查询
mysql> insert into employees(name) values ("bob"),("tom"),("lily");
# 显示没有部门的员工名
mysql> select emp.name,dep.dept_name from departments dep right join employees emp on emp.dept_id=dep.dept_id where emp.dept_id is null;
#3. 全外连接查询
#1)输出2018年基本工资的最大值和最小值
mysql> (select basic from salary where year(date)=2018 order by basic desc limit 1) union (select basic from salary where year(date)=2018 order by basic limit 1);
#2)输出2018年1月10号基本工资的最大值和最小值
mysql> (select date , max(basic) as 工资 from salary where date=20180110)union(select date,min(basic) from salary where date=20180110);
#3)union all 不去重显示查询结果
mysql> (select employee_id , name , birth_date from employees where employee_id <= 5) union all (select employee_id , name , birth_date from employees where employee_id <= 6);
嵌套查询
嵌套查询:是指在一个完整的查询语句之中,包含若干个不同功能的小查询;从而一起完成复杂查询的一种编写形式。包含的查询放在()里 , 包含的查询出现的位置:
- SELECT之后
- FROM之后
- WHERE
- HAVING之后
#1. where之后嵌套查询
#1)查询运维部所有员工信息
mysql> select * from employees where dept_id = (select dept_id from departments where dept_name="运维部");
#2)查询人事部2018年12月所有员工工资
mysql> select * from salary where year(date)=2018 and month(date)=12 and employee_id in (select employee_id from employees where dept_id=(select dept_id from departments where dept_name='事部') );
#3)查询人事部和财务部员工信息
mysql> select dept_id , name from employees where dept_id in ( select dept_id from departments where dept_name in ('人事部', '财务部') );
#4)查询2018年12月所有比100号员工基本工资高的工资信息
mysql> select * from salary where year(date)=2018 and month(date)=12 and basic>(select basic from salary where year(date)=2018 and month(date)=12 and employee_id=100);
#2. having之后嵌套查询
#查询部门员工总人数比开发部总人数少 的 部门名称和人数
mysql> select dept_id ,count(name) as total from employees group by dept_id having total < ( select count(name) from employees where dept_id=( select dept_id from departments where dept_name='开发部') );
#3. from之后嵌套查询
#查询3号部门 、部门名称 及其部门内 员工的编号、名字 和 email
mysql> select dept_id, dept_name, employee_id, name, email from ( select d.dept_name, e.* from departments as d inner join employees as e on d.dept_id=e.dept_id ) as tmp_table where dept_id=3;
#4. select之后嵌套查询
#查询每个部门的人数: dept_id dept_name 部门人数
mysql> select d.* , ( select count(name) from employees as e where d.dept_id=e.dept_id) as 部门人数 from departments as d;