2.模拟问题——5.星期几与字符串对应

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输入输出示例

输入：
9 October 2001
14 October 2001
输出：
Tuesday
Sunday

【原题链接】

字符串处理

C风格的字符串

字符数组，以’\0‘结尾
建议在输入输出语句中使用

C++风格的字符串

#include <string>
using namespace std;

初始化：string str1 = str;//world
连接： str1 + “hello” //即"worldhello"
字符：str1[0]//即’w’
长度：str1.length();
判断相符：str1 == “world”
比较字典顺序：str1 > “abandon”
从C++风格到C风格：str1.c_str();

字符串到数字的对应：map映射

#include <map>
using namespace std;

    map<string,string> myMap = {//<键key的类型，值value的类型>{"Caixukun","ikun"},{"Wuyifan","meigeni"}};char str[100];scanf("%s",str);string name = str;printf("%s的粉丝被称为%s\n",name.c_str(),myMap[name].c_str());

星期的计算

根据今天是星期几，计算要求日期距离今天的距离，然后计算其星期数即可

#include <cstdio>
#include <string>
#include <map>
using namespace std;
int main() {map<string,int> month2int = {{"January",1},{"February",2},{"March",3},{"April",4},{"May",5},{"June",6},{"July",7},{"August",8},{"September",9},{"October",10},{"November",11},{"December",12}};int month_Day[13]={0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};string int2Weekday[7] = {"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"};int year, mon, day;char str[100];string month;bool isBefore;//在过去还是在未来while(scanf("%d%s%d",&day,str,&year)!=EOF){month = str;//把字符串从C风格转换成C++风格mon = month2int[month];if (year < 2024||2024 == year && mon <3 || 2024 ==year &&mon==3&&day <10){isBefore= true;}else{isBefore= false;}//从begin走到endint beginYear, beginMon, beginDay, endYear, endMonth, endDay;if (isBefore){beginYear = year;beginMon = mon;beginDay = day;endYear = 2024;endMonth = 3;endDay = 10;} else{beginYear = 2024;beginMon = 3;beginDay = 10;endYear = year;endMonth = mon;endDay = day;}//2024年3月10日是星期日int totalDay = 0;while(true){if (beginYear==endYear&&beginMon==endMonth&&beginDay==endDay){break;}++totalDay;//next daybool isLeap = beginYear%400==0||beginYear%100!=0&&beginYear%4==0;if(isLeap){month_Day[2]=29;} else{month_Day[2]=28;}++beginDay;if (beginDay>month_Day[beginMon]){beginDay = 1;++beginMon;if (beginMon>12){beginMon=1;beginYear++;}}}if (isBefore){printf("%s\n",int2Weekday[7-totalDay%7].c_str());}else{printf("%s\n",int2Weekday[(totalDay)%7].c_str());}}return 0;
}