c语言 函数的参数传递示例

C ++ llround()函数 (C++ llround() function)

llround() function is a library function of cmath header, it is used to round the given value and casts to a long long integer, it accepts a number and returns the integer (long long int) value that is nearest to the number (with halfway cases).

llround()函数是cmath标头的库函数，用于舍入给定值并将其转换为长整型整数，它接受一个数字并返回最接近该数字的整数(长整型int)值(带有中途案例)。

Syntax of llround() function:

llround()函数的语法：

    llround(x);

Parameter(s): x – is the number to round nearest to zero with halfway cases.

参数： x –是中途取整的数字，最接近零。

Return value: long long int – it returns long long int type value that is the rounded value of the number x.

返回值： long long int –返回long long int类型值，该值是数字x的舍入值。

Example:

例：

    Input:
float x = 2.3;    
Function call:
llround(x);    
Output:
2
Input:
float x = 2.8;
Function call:
llround(x);    
Output:
3

C ++代码演示llround()函数的示例 (C++ code to demonstrate the example of llround() function)

// C++ code to demonstrate the example of 
// llround() function
#include <iostream>
#include <cmath>
using namespace std;
// main() section
int main()
{
float x;
x = 15.3;
cout<<"llround("<<x<<"): "<<llround(x)<<endl;
x = 15.5;
cout<<"llround("<<x<<"): "<<llround(x)<<endl;
x = 15.8;
cout<<"llround("<<x<<"): "<<llround(x)<<endl;
x = -15.3;
cout<<"llround("<<x<<"): "<<llround(x)<<endl;
x = -15.5;
cout<<"llround("<<x<<"): "<<llround(x)<<endl;
x = -15.8;
cout<<"llround("<<x<<"): "<<llround(x)<<endl;    
return 0;
}

Output

输出量

llround(15.3): 15
llround(15.5): 16
llround(15.8): 16
llround(-15.3): -15
llround(-15.5): -16
llround(-15.8): -16

翻译自: https://www.includehelp.com/cpp-tutorial/llround-function-with-example.aspx

c语言 函数的参数传递示例