博弈论 斯坦福game theory stanford week 3.2_


title: 博弈论 斯坦福game theory stanford week 3-1
tags: note
notebook: 6- 英文课程-15-game theory
---

博弈论 斯坦福game theory stanford week 3-1

习题

第 1 个问题

img_5d8fa8d4ec2efce7a8e96c6cf9172115.png

We say that a game is dominance solvable, if iterative deletion of strictly dominated strategies yields a unique outcome. True or false: The above game si dominance solvable. Hint: Consider both pure strategies and mixed strategies to do your domination.

a) True;

正确 
(a) is correct, the game is dominance solvable.For player 2, R is dominated by a mixed strategy between L and M (for example, play L with probability 1/2 and M with probability 1/2).
Once R is removed, for player 1 D is dominated by U.
Finally, once R and D are removed, M is dominated by L.
Since the process of iterative deletion of strictly dominated strategies yields the unique outcome (U,L), the game is dominance solvable.

b) False.

第 2 个问题

正确
1 / 1 分
2。第 2 个问题
In order to illustrate the problem that arises when iteratively eliminating weakly dominated strategies, consider the following game:

img_5d8fa8d4ec2efce7a8e96c6cf9172115.png

True or false: in the above game the order of elimination of weakly dominated strategies does not matter (that is, the final outcome is the same regardless of the order in which weakly dominated strategies are eliminated.).

[Hint: start the process of iterative elimination of weakly dominated strategies by eliminating different strategies at the beginning of the process.]

a) True;

b) False.

正确 
(b) is correct, in the previous game the order of elimination of weakly dominated strategies does matter.Consider the following attempts:
If we start by eliminating the weakly dominated strategy L:
For 2, L is weakly dominated by R.
Once L is removed, for 1 U is weakly dominated by D.
Once L and U are removed, M is strictly dominated by R.
The outcome of this process of elimination is (D,R).
If we start by eliminating the weakly dominated strategy M:
For 2, M is weakly dominated by R.
Once M is removed, for 1 D is weakly dominated by U.
Once M and D are removed, L is strictly dominated by R.
The outcome of this process of elimination is (U,R).
Then, the order of elimination of weakly dominated strategies does affect the outcome of the process.

第 3 个问题
正确
1 / 1 分

3。第 3 个问题

Consider the matching pennies game:

img_4e78d3e350ddef5e02491795ea90276d.png

Which is a maxmin strategy for player 1:

a) Play Left.

b) Play Right.

c) Play Left and Right with probability 1/2.

正确 
(c) is true.Recall from lecture: S1=argmaxs′1∈S1mins2∈S2u1(s′1,s2)
Given a strategy of 1: play Left with probability p and Right with 1−p (0≤p≤1):
If p>1/2, s2=Right leads 1 to earn (−2)p+2(1−p)<0;
If p<1/2, s2=Left leads 1 to earn 2p+(−2)(1−p)<0;
If p=1/2, then regardless of 2's strategy 1 earns 0.
Thus p=1/2 is the maxmin strategy.

d) It doesn't exist.

第 4 个问题

正确
1 / 1 分
4。第 4 个问题
Consider the matching pennies game:

img_00652fdc20dadfec04a87a5e8b53cdc6.png

Apply the Minimax theorem presented in lecture 3-4 to find the payoff that any player must receive in any Nash Equilibrium:

a) 2;

b) -2;

c) 1;

d) 0.

正确 
(d) is true.Since the previous game is a (finite) two-player, zero-sum game, by the theorem presented in the lecture we know that in any Nash equilibrium each player receives a payoff that is equal to both his maximin value and his minimax value.
From the previous question we know that each player's maximin strategy is to play Left and Right with probability 1/2, which gives an expected payoff (maximin value) of 0.

第 5 个问题

正确
1 / 1 分
5。第 5 个问题
img_e946047d6d0a6437faed171541e36809.png

Consider the following assignment device (for example a fair coin):

With probability 1/2 it tells players 1 and 2 to play B, and with probability 1/2 it tells them to play F.
Both players know that the device will follow this rule.
What is the expected payoff of each player when both players follow the recommendations made by the device? If one of players follows the recommendation, does the other player have an incentive to follow the recommendation as well?

a) Expected payoff =2; player has an incentive to follow the recommendation.

b) Expected payoff =1; player does not an incentive to follow the recommendation.

c) Expected payoff =1.5; player has an incentive to follow the recommendation.

正确 
(c) is true.If both players follow the recommendation of the device, they will play (B,B) with probability 1/2 and (F,F) with probability 1/2. Then, the expected payoff is 1/2∗2+1/2∗1=1.5.
It is easy to check that if one of the players is following the recommendation, then the other player has an incentive to do the same:
Suppose that player 1 follows the recommendation of the device.
When player 2 is told to play B, he/she knows that player 1 was also told to play B (and that is the strategy that he/she will play).
Player's 2 best response to player 1 playing B is to also play B.
The same holds when player 2 is told to play F. Therefore, player 2 will follow what the device tells him/her to do.

d) Expected payoff =1.5; player does not have an incentive to follow the recommendation.

本文来自互联网用户投稿,该文观点仅代表作者本人,不代表本站立场。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如若转载,请注明出处:http://www.mzph.cn/news/539245.shtml

如若内容造成侵权/违法违规/事实不符,请联系多彩编程网进行投诉反馈email:809451989@qq.com,一经查实,立即删除!

相关文章

nestjs swagger文档调用需要鉴权的接口

目标 nestjs经常需要设置一些鉴权&#xff08;登录后&#xff09;才能访问的接口&#xff0c;但是生成的swagger文档可以发起接口请求&#xff0c;文档发起的请求默认是不携带登录token的&#xff0c;所以需要移除swagger文档发起请求的守卫拦截。 nestjs守卫拦截设置见另一篇…

ajax预加载html seo,前端性能优化 — JS预加载和懒加载

JS预加载需求&#xff1a;有时我们需要实现例如快速快速切换页面、图片之类的功能时&#xff0c;能尽快的加载出我们所需的图片会极大提升用户体验&#xff0c;这时用预加载将图片先缓存到浏览器&#xff0c;用户使用需显示图片时无疑会顺畅很多。核心&#xff1a;当一个图片在…

和平精英显示服务器人数太多,和平精英到底有多差 导致玩家纷纷国际服

原标题&#xff1a;和平精英到底有多差 导致玩家纷纷国际服和平精英上线以来争议不断&#xff0c;百分之九十九是对和平精英的各种不满&#xff0c;还有百分之一是喜欢和平精英&#xff0c;认为刺激战场已经免费给我们玩&#xff0c;让腾讯亏了很多钱&#xff0c;现在和平精英上…

python中的wx_配置 Python的wxWidgets可视开发环境 | 学步园

注&#xff1a;转载请注明出处 一、下载 Python 2.5.1 这一步是必须做的&#xff0c;下载 Python 语言的 SDK 下载地址(直接复制到迅雷)&#xff1a;点击下载 下载完成后安装 Python 2.5.1&#xff0c;注意安装路径中不要有空格&#xff0c;不然会引起一些问题。 二、下载 wxPy…

的write方法有哪些参数_向子进程传递大量数据的方法

如何传递大型数据给子进程昨天的一篇文章中&#xff0c;我们说到如果想向一个子进程传输多于32767个字符的数据&#xff0c;我们需要寻找其他的方法(而不是命令行参数)来实现。我们能想到的第一个方法是&#xff1a;WM_COPYDATA。当子进程创建并进入消息循环后&#xff0c;我们…

厉害了!中关村软件园人工智能军团有料有看点

人工智能已成为当下全球科技界的新热点&#xff0c;中外竞相攀登这座划时代的科技高峰。上月&#xff0c;国务院印发《新一代人工智能发展规划》&#xff0c;明确将人工智能作为未来国家重要的发展战略。《规划》提出前瞻布局新一代人工智能重大科技项目&#xff0c;到2030年中…

Hive的使用之hwi

概述 hwi是hive开发的网页形式查看数据。方便非专业人士使用。 安装步骤 1、下载hive源码包 地址&#xff1a;http://apache.fayea.com/hive/ apache-hive-2.1.0-src.tar.gz 2、打包war 解压apache-hive-2.1.0-src.tar.gz源码包&#xff0c;进入到 C:\Users\zengmg\Deskto…

c 服务器传输大文件,cend.me:不须经过服务器,直接点对点的文件传输免费服务...

要传送文件给远程的手机、平板、电脑等设备&#xff0c;通常的做法就是先将文件上传到服务器存放&#xff0c;然后再从服务器下载&#xff0c;这样的做法看似合理&#xff0c;但如果上传的同时就由远程的设备来接收&#xff0c;不要经过服务器&#xff0c;这样就能更节省上、下…

Thrift源码学习二——Server层

Thrift 提供了如图五种模式&#xff1a;TSimpleServer、TNonblockingServer、THsHaServer、TThreadPoolServer、TThreadSelectorServer ​​ TSimpleServer、TThreadPoolServer 属于阻塞模型 TNonblockingServer、THsHaServer、TThreadedSelectorServer 属于非阻塞模型 TServer…

base64是哪个jar包的_涨知识 | 用maven轻松管理jar包

前言相信只要做过 Java 开发的童鞋们&#xff0c;对 Ant 想必都不陌生&#xff0c;我们往往使用 Ant 来构建项目&#xff0c;尤其是涉及到特别繁杂的工作量&#xff0c;一个 build.xml 能够完成编译、测试、打包、部署等很多任务&#xff0c;这在很大的程度上解放了程序员们的双…

JMS(Java消息服务)与消息队列ActiveMQ基本使用(一)

最近的项目中用到了mq&#xff0c;之前自己一直在码农一样的照葫芦画瓢。最近几天研究了下&#xff0c;把自己所有看下来的文档和了解总结一下。 一. 认识JMS 1.概述 对于JMS,百度百科&#xff0c;是这样介绍的&#xff1a;JMS即Java消息服务&#xff08;Java Message Service&…

hive复合数据类型之struct

概述 STRUCT&#xff1a;STRUCT可以包含不同数据类型的元素。这些元素可以通过”点语法”的方式来得到所需要的元素&#xff0c;比如user是一个STRUCT类型&#xff0c;那么可以通过user.address得到这个用户的地址。 操作实例 1、创建表 create table student_test(id int,in…

hive复合数据类型之array

概述 ARRAY&#xff1a;ARRAY类型是由一系列相同数据类型的元素组成&#xff0c;这些元素可以通过下标来访问。比如有一个ARRAY类型的变量fruits&#xff0c;它是由[apple,orange,mango]组成&#xff0c;那么我们可以通过fruits[1]来访问元素orange&#xff0c;因为ARRAY类型的…

hive复合数据类型之map

概述 MAP&#xff1a;MAP包含key->value键值对&#xff0c;可以通过key来访问元素。比如”userlist”是一个map类型&#xff0c;其中username是key&#xff0c;password是value&#xff1b;那么我们可以通过userlist[username]来得到这个用户对应的password&#xff1b; 操…

Beego框架使用

为什么80%的码农都做不了架构师&#xff1f;>>> Beego Web项目目录结构 new 命令是新建一个 Web 项目&#xff0c;我们在命令行下执行 bee new <项目名> 就可以创建一个新的项目。但是注意该命令必须在 $GOPATH/src 下执行。最后会在 $GOPATH/src 相应目录下…

oracle下lag和lead分析函数

Lag和Lead分析函数可以在同一次查询中取出同一字段的前N行的数据(Lag)和后N行的数据(Lead)作为独立的列。 这种操作可以代替表的自联接&#xff0c;并且LAG和LEAD有更高的效率。 语法&#xff1a; [sql] view plaincopy /*语法*/ lag(exp_str,offset,defval) over() Lead(…

jtessboxeditorfx 界面显示不出来_macOS 使用 XQuartz 支持 X11 实现 Linux 图形化界面显示...

更多奇技淫巧欢迎订阅博客&#xff1a;https://fuckcloudnative.io前言在 Windows 中相信大家已经很熟悉使用 Xmanager(Xshell), MobaXterm, SecureCRT 通过 X11 实现 Linux 图形化界面显示&#xff0c;我的需求是在 macOS 下使用 iTerm2 作为 Terminal 实现 X11 图形化界面显示…

EntityFramework Core 2.0 Explicitly Compiled Query(显式编译查询)

前言 EntityFramework Core 2.0引入了显式编译查询&#xff0c;在查询数据时预先编译好LINQ查询便于在请求数据时能够立即响应。显式编译查询提供了高可用场景&#xff0c;通过使用显式编译的查询可以提高查询性能。EF Core已经使用查询表达式的散列来表示自动编译和缓存查询&a…

.net 导出excel_Qt编写的项目作品18-数据导出到Excel及Pdf和打印数据

一、功能特点原创导出数据机制&#xff0c;不依赖任何office组件或者操作系统等第三方库&#xff0c;尤其是支持嵌入式linux。10万行数据9个字段只需要2秒钟完成。只需要四个步骤即可开始急速导出大量数据到Excel。同时提供直接写入数据接口和多线程写入数据接口&#xff0c;不…

图像增强_Keras 常用的图像增强方式

欢迎关注 “小白玩转Python”&#xff0c;发现更多 “有趣”在使用神经网络和深度学习模型时&#xff0c;需要进行数据准备。对于更复杂的物体识别任务&#xff0c;也越来越需要增加数据量。数据增加意味着增加数据量。换句话说&#xff0c;拥有更大的数据集意味着更健壮的模型…