Dish Shopping
将每个物品拆成p 和 s 再加上人排序。 然后问题就变成了， 对于一个线段(L - R)，
问有多少个(li, ri)满足 L >= li && R >= ri， 这个东西可以直接树状数组套平衡树维护。
但是这个题目有个特殊性，因为排好序之后不会存在 li > L && ri > R的点， 所以可以直接
用平衡树， 或者线段树去维护这个东西。
平板电视
#include<bits/stdc++.h> #include <bits/extc++.h> #define LL long long #define fi first #define se second #define mk make_pair #define PLL pair<LL, LL> #define PLI pair<LL, int> #define PII pair<int, int> #define SZ(x) ((int)x.size()) #define ull unsigned long longusing namespace std; using namespace __gnu_pbds;const int N = 1e5 + 7; const int inf = 0x3f3f3f3f; const LL INF = 0x3f3f3f3f3f3f3f3f; const int mod = 998244353; const double eps = 1e-6; const double PI = acos(-1);int n, m, tot, ans[N * 3], hs[N], cnt; int p[N], s[N], b[N], inc[N], pref[N];struct event {int p, b, id, op, rp;bool operator < (const event& rhs) const {if(p == rhs.p) return op < rhs.op;else return p < rhs.p;} } e[N * 3];template <class T> using Tree = tree<T, null_type, std::less<T>, rb_tree_tag,tree_order_statistics_node_update>;struct Bit {Tree<PII> T[N];void add(int x, PII v) {for(int i = x; i <= cnt; i += i & -i)T[i].insert(v);}void del(int x, PII v) {for(int i = x; i <= cnt; i += i & -i)T[i].erase(v);}int sum(int x, int R) {int ans = 0;for(int i = x; i; i -= i & -i)ans += T[i].order_of_key(mk(R, INT_MAX));return ans;} } bit;int getPos(int x) {return upper_bound(hs + 1, hs + 1 + cnt, x) - hs - 1; }int main() {scanf("%d%d", &n, &m);for(int i = 1; i <= n; i++) scanf("%d", &p[i]);for(int i = 1; i <= n; i++) scanf("%d", &s[i]);for(int i = 1; i <= n; i++) scanf("%d", &b[i]);for(int i = 1; i <= n; i++) {e[++tot] = event{p[i], b[i], i, 0, p[i]};e[++tot] = event{s[i], b[i], i, 2, p[i]};hs[++cnt] = p[i] - b[i];}for(int i = 1; i <= m; i++) scanf("%d", &inc[i]);for(int i = 1; i <= m; i++) scanf("%d", &pref[i]);for(int i = 1; i <= m; i++) e[++tot] = event{inc[i], pref[i], n + i, 1, 0};sort(hs + 1, hs + 1 + cnt);cnt = unique(hs + 1, hs + 1 + cnt) - hs - 1;sort(e + 1, e + 1 + tot);for(int i = 1; i <= tot; i++) {int p = e[i].p, b = e[i].b, rp = e[i].rp;if(e[i].op == 0) {bit.add(getPos(rp - b), mk(rp + b, e[i].id));} else if(e[i].op == 1) {ans[e[i].id] = bit.sum(getPos(p - b), p + b);} else {bit.del(getPos(rp - b), mk(rp + b, e[i].id));}}for(int i = n + 1; i <= n + m; i++) printf("%d ", ans[i]);puts("");return 0;}/* */
treap, 为啥我的treap好慢啊啊啊。
#include<bits/stdc++.h> #define LL long long #define fi first #define se second #define mk make_pair #define PLL pair<LL, LL> #define PLI pair<LL, int> #define PII pair<int, int> #define SZ(x) ((int)x.size()) #define ull unsigned long longusing namespace std;const int N = 1e5 + 7; const int inf = 0x3f3f3f3f; const LL INF = 0x3f3f3f3f3f3f3f3f; const int mod = 998244353; const double eps = 1e-6; const double PI = acos(-1);mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());int n, m, tot, ans[N * 3], hs[N], cnt; int p[N], s[N], b[N], inc[N], pref[N];struct event {int p, b, id, op, rp;bool operator < (const event& rhs) const {if(p == rhs.p) return op < rhs.op;else return p < rhs.p;} } e[N * 3];struct node {node* ch[2];int key, fix, sz, cnt;void update() {sz = ch[0]->sz + ch[1]->sz + cnt;} } base[N * 20];typedef node* P_node; P_node len = base;struct Treap {node nil;P_node root, null;Treap() {root = null = &nil;null->key = null->fix = inf;null->sz = null->cnt = 0;null->ch[0] = null->ch[1] = null;}P_node newnode(int tkey) {len->key = tkey;len->fix = rng();len->ch[0] = len->ch[1] = null;len->sz = len->cnt = 1;return len++;}void rot(P_node &p, int d) {P_node k = p->ch[d ^ 1];p->ch[d ^ 1] = k->ch[d];k->ch[d] = p;p->update();k->update();p = k;}void _Insert(P_node &p, int tkey) {if(p == null) {p = newnode(tkey);} else if(p->key == tkey) {p->cnt++;} else {int d = tkey > p->key;_Insert(p->ch[d], tkey);if(p->ch[d]->fix > p->fix) {rot(p, d ^ 1);}}p->update();}void _Delete(P_node &p, int tkey) {if(p == null) return;if(p->key == tkey) {if(p->cnt > 1) p->cnt--;else if(p->ch[0] == null) p = p->ch[1];else if(p->ch[1] == null) p = p->ch[0];else {int d = p->ch[0]->fix > p->ch[1]->fix;rot(p, d);_Delete(p->ch[d], tkey);}} else {_Delete(p->ch[tkey > p->key], tkey);}p->update();}int _Kth(P_node p, int k) {if(p == null || k < 1 || k > p->sz) return 0;if(k < p->ch[0]->sz + 1) return _Kth(p->ch[0], k);if(k > p->ch[0]->sz + p->cnt) return _Kth(p->ch[1], k - p->ch[0]->sz - p->cnt);return p->key;}int _Rank(P_node p, int tkey, int res) {if(p == null) return -1;if(p->key == tkey) return p->ch[0]->sz + res + 1;if(tkey < p->key) return _Rank(p->ch[0], tkey, res);return _Rank(p->ch[1], tkey, res + p->ch[0]->sz + p->cnt);}int _Pred(P_node p, int tkey){if(p == null) return -inf;if(tkey <= p->key) return _Pred(p->ch[0], tkey);return max(p->key, _Pred(p->ch[1], tkey));}int _Succ(P_node p, int tkey){if(p == null) return inf;if(tkey >= p->key) return _Succ(p->ch[1], tkey);return min(p->key, _Succ(p->ch[0], tkey));}int _Query(P_node p, int tkey) {if(p == null) return 0;if(p->key > tkey) return _Query(p->ch[0], tkey);else if(p->key < tkey) return p->cnt + p->ch[0]->sz + _Query(p->ch[1], tkey);else return p->cnt + p->ch[0]->sz;}void Insert(int tkey){ _Insert(root,tkey); }void Delete(int tkey){ _Delete(root,tkey); }int Kth(int k){ return _Kth(root,k); }int Rank(int tkey){ return _Rank(root,tkey,0); }int Pred(int tkey){ return _Pred(root,tkey); }int Succ(int tkey){ return _Succ(root,tkey); }int Query(int tkey){ return _Query(root, tkey); } }tp;struct Bit {Treap T[N];void add(int x, int v) {for(int i = x; i <= cnt; i += i & -i)T[i].Insert(v);}void del(int x, int v) {for(int i = x; i <= cnt; i += i & -i)T[i].Delete(v);}int sum(int x, int R) {int ans = 0;for(int i = x; i; i -= i & -i)ans += T[i].Query(R);return ans;} } bit;int getPos(int x) {return upper_bound(hs + 1, hs + 1 + cnt, x) - hs - 1; }int main() {srand(time(NULL));scanf("%d%d", &n, &m);for(int i = 1; i <= n; i++) scanf("%d", &p[i]);for(int i = 1; i <= n; i++) scanf("%d", &s[i]);for(int i = 1; i <= n; i++) scanf("%d", &b[i]);for(int i = 1; i <= n; i++) {e[++tot] = event{p[i], b[i], i, 0, p[i]};e[++tot] = event{s[i], b[i], i, 2, p[i]};hs[++cnt] = p[i] - b[i];}for(int i = 1; i <= m; i++) scanf("%d", &inc[i]);for(int i = 1; i <= m; i++) scanf("%d", &pref[i]);for(int i = 1; i <= m; i++) e[++tot] = event{inc[i], pref[i], n + i, 1, 0};sort(hs + 1, hs + 1 + cnt);cnt = unique(hs + 1, hs + 1 + cnt) - hs - 1;sort(e + 1, e + 1 + tot);for(int i = 1; i <= tot; i++) {int p = e[i].p, b = e[i].b, rp = e[i].rp;if(e[i].op == 0) {bit.add(getPos(rp - b), rp + b);} else if(e[i].op == 1) {ans[e[i].id] = bit.sum(getPos(p - b), p + b);} else {bit.del(getPos(rp - b), rp + b);}}for(int i = n + 1; i <= n + m; i++) printf("%d ", ans[i]);puts("");return 0;}/* */
