TestDao.java（测试类）
@Test
public void findCollectionByConditionNoPage(){
ApplicationContext ac = new ClassPathXmlApplicationContext("beans.xml");
IElecTextService elecTextService = (IElecTextService) ac.getBean(IElecTextService.SERVICE_NAME);
//封装查询条件
ElecText electText = new ElecText();
electText.setTextName("李");
electText.setTextRemark("李");
//在service中组织查询条件，查询结果
List<ElecText> list = elecTextService.findCollectionByConditionNoPage(electText);
if(list!=null && list.size()>0){
for (ElecText text : list) {
System.out.println(text.toString());
}
}
}
ElecTextServiceImpl.java(service层实现类)
//增删改的方法：添加：@Transactional(isolation=Isolation.DEFAULT,propagation=Propagation.REQUIRED,readOnly=false)
//查询的方法：不需要添加
/**
* SELECT * FROM elec_text o WHERE 1=1
AND o.textName LIKE '%李%'
AND o.textRemark LIKE '%李%'
ORDER BY o.textDate DESC,o.textName ASC
*/
public List<ElecText> findCollectionByConditionNoPage(ElecText electText) {
//组织查询条件
String condition = "";
List<Object> paramsList = new ArrayList<Object>();//存放'?'对应的可变参量
//名称
String textName = electText.getTextName();
if(StringUtils.isNotBlank(textName)){
condition += " AND o.textName LIKE ?";
paramsList.add("%"+textName+"%");
}
//备注
String textRemark = electText.getTextRemark();
if(StringUtils.isNotBlank(textRemark)){
condition += " AND o.textRemark LIKE ?";
paramsList.add("%"+textRemark+"%");
}
//将paramsList转换成数组
Object [] params = paramsList.toArray();
//排序
Map<String, String> orderby = new LinkedHashMap<String, String>();
orderby.put("o.textDate", "desc");
orderby.put("o.textName", "asc");
List<ElecText> list = elecTextDao.findCollectionByConditionNoPage(condition,params,orderby);
return list;
}
CommonDaoImpl.java(底层方法封装CommonDaoImpl类，Dao层)
//指定查询条件，查询对应的集合List（单表）
/**
* SELECT * FROM elec_text o WHERE 1=1
AND o.textName LIKE '%李%'
AND o.textRemark LIKE '%李%'
ORDER BY o.textDate DESC,o.textName ASC
*/
public List<T> findCollectionByConditionNoPage(String condition,
Object[] params, Map<String, String> orderby) {
String hql = " FROM "+entityClass.getSimpleName()+" o WHERE 1=1 ";
//ORDER BY o.textDate DESC,o.textName ASC
String orderbyHql = orderby(orderby);
String finalHql = hql + condition + orderbyHql;
//执行hql语句
List<T> list = this.getHibernateTemplate().find(finalHql,params);
return list;
}
//解析map集合，获取orderby的排序条件
private String orderby(Map<String, String> orderby){
StringBuffer buffer = new StringBuffer("");
if(orderby!=null && orderby.size()>0){
buffer.append(" ORDER BY ");
for(Map.Entry<String, String> map:orderby.entrySet()){
buffer.append(map.getKey()).append(map.getValue()).append(",");
}
//删除最后一个逗号
buffer.deleteCharAt(buffer.length()-1);
}
return buffer.toString();
}
Service层下orderby.put("o.textDate ", "desc"); 不加空格会报错
错误提示如下：
Caused by: org.hibernate.QueryException: could not resolve property: textDatedesc of: cn.itcast.elec.domain.ElecText [ FROM cn.itcast.elec.domain.ElecText o WHERE 1=1 AND o.textName LIKE ? AND o.textRemark LIKE ? ORDER BY o.textDatedesc,o.textNameasc]
出现错误的代码如下：
//排序
Map<String, String> orderby = new LinkedHashMap<String, String>();
orderby.put("o.textDate", "desc");
orderby.put("o.textName", "asc");
List<ElecText> list = elecTextDao.findCollectionByConditionNoPage(condition,params,orderby);
return list;
)
