2023每日刷题（六十七）

Leetcode—LCR 025.两数相加II

实现代码

/*** Definition for singly-linked list.* struct ListNode {*     int val;*     struct ListNode *next;* };*/struct ListNode* addTwoNumbers(struct ListNode* l1, struct ListNode* l2){struct ListNode* head1 = (struct ListNode*)malloc(sizeof(struct ListNode));head1->next = NULL;struct ListNode* head2 = (struct ListNode*)malloc(sizeof(struct ListNode));head2->next = NULL;struct ListNode* p, *q, *p2, *q2;p = l1;p2 = l1->next;q = l2;q2 = l2->next;// 链表翻转while(p != NULL) {p->next = head1->next;head1->next = p;p = p2;if(p2 == NULL) {break;}p2 = p2->next;}while(q != NULL) {q->next = head2->next;head2->next = q;q = q2;if(q2 == NULL) {break;}q2 = q2->next;}p = head1->next;q = head2->next;head1->next = NULL;int c = 0;while(p && q) {struct ListNode* s = (struct ListNode*)malloc(sizeof(struct ListNode));s->next = NULL;int sum = p->val + q->val + c;c = sum / 10;s->val = sum % 10;s->next = head1->next;head1->next = s;p = p->next;q = q->next;}while(p != NULL) {struct ListNode* s = (struct ListNode*)malloc(sizeof(struct ListNode));s->next = NULL;int sum = p->val + c;c = sum / 10;s->val = sum % 10;s->next = head1->next;head1->next = s;p = p->next;}while(q != NULL) {struct ListNode* s = (struct ListNode*)malloc(sizeof(struct ListNode));s->next = NULL;int sum = q->val + c;c = sum / 10;s->val = sum % 10;s->next = head1->next;head1->next = s;q = q->next;}if(c) {struct ListNode* s = (struct ListNode*)malloc(sizeof(struct ListNode));s->next = NULL;s->val = c;s->next = head1->next;head1->next = s;}return head1->next;
}

运行结果

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