高精度数组的集大成

做的时候在和高中同学叙叙旧，差点寄掉

代码如下：

#include<stdio.h>
void expand(int len);
const char hexadecimal[17] = "0123456789ABCDEF";
int result[20], mid[20], l_result[100];int main(void)
{char tmp;int len, length = 0, len2 = 1;scanf("%c %d", &tmp, &len);for(int i = 0; i <= 15; i++)if(hexadecimal[i] == tmp){mid[len - 1] = i;break;}while(mid[len - 1] <= 15){int ext = 0, i;expand(len);for(i = 0; i < len; i++){ext += result[i] + mid[i];result[i] = ext % 16;ext /= 16;}while(ext){ext += result[i];result[i++] = ext % 16;ext /= 16;}length = (length > i) ? length : i;mid[len - 1]++;}//转换for(int i = length - 1; i >= 0; i--){int ext = 0, j;for(j = 0; j < len2; j++){ext += l_result[j] * 16;l_result[j] = ext % 10;ext /= 10;}while(ext){ext += l_result[j];l_result[j++] = ext % 10;ext /= 10;}len2 = (len2 > j) ? len2 : j;ext = result[i], j = 0;while(ext){ext += l_result[j];l_result[j++] = ext % 10;ext /= 10;}len2 = (len2 > j) ? len2 : j;}//输出for(int i = len2 - 1; i >= 0; i--)printf("%d", l_result[i]);return 0;
}
void expand(int len)
{for(int i = len - 2, j = 1; i >= 0; i--, j++)mid[i] = (mid[len - 1] + j) % 16;return;
}

写的有点草，进制的转换方法我之前写过，就不赘述了