Java宝藏实验资源库（3）类

一、实验目的

理解面向对象程序的基本概念。
掌握类的继承的实现机制。
熟悉类中成员的访问控制方法。
熟悉ArrayList类的使用。

二、实验内容、过程及结果

*9.5Programming Exerc
ise the GregorianCal endar class) Java API has the GregorianCalendar class in the java. uti7 package, which you can use to obtain the year, month, and day of a date. The no-arg constructor constructs an instance for the current date, and the methods get(GregorianCalendar.YEAR), get(GregorianCalendar.MONTH),and get(GregorianCalendar. DAY_OF_MONTH) return the year, month, and day.Write a program to perform two tasks:
■ Display the current year, month, and day.
The GregorianCalendar class has the setTimeInMillis(long), which can be used to set a specified elapsed time since January 1, 1970. Set the value to 1234567898765L and display the year, month, and day.

*9.5编程Exerc Java API在Java中有GregorianCalendar类。Uti7包，您可以使用它来获取日期的年、月和日。无参数构造函数为当前日期构造一个实例，并使用get(GregorianCalendar. year)、get(GregorianCalendar. month)和get(GregorianCalendar)方法。DAY_OF_MONTH)返回年、月、日。编写一个程序来执行两个任务: ■显示当前的年、月、日。 GregorianCalendar类具有setTimeInMillis(long)，可用于设置指定的经过时间。

运行代码如下：

package chapter09;
import java.util.GregorianCalendar;
class Code_05 {public static void main(String[] args){GregorianCalendar calendar = new GregorianCalendar();System.out.println(calendar.get(calendar.YEAR) + ":" + calendar.get(calendar.MONTH) + ":" + calendar.get(calendar.DAY_OF_MONTH));calendar.setTimeInMillis(1234567898765L);System.out.println(calendar.get(calendar.YEAR) + ":" + calendar.get(calendar.MONTH) + ":" + calendar.get(calendar.DAY_OF_MONTH));}
}

运行结果

*9.10 (Algebra: quadratic equations) Design a class named QuadraticEquation fora quadratic equation ax2 + bx + x = 0. The class contains:

■ Private data fields a, b, and c that represent three coefficients.

■ A constructor for the arguments for a, b, and c.

■ Three getter methods for a, b, and c

*9.10（代数：二次方程式）为二次方程式ax2+bx+c=0设计一个名 QuadraticEquation的类。这个类包括：

■ 代表三个系数的私有成员变量a、b和c。

■ 一个参数为a、b和c的构造方法。

■ a、b、c 的三个get 方法。

运行代码如下：

Main.java
import java.util.Scanner;
class Unite9Test10
{public static void main(String[] args){Scanner input = new Scanner(System.in);System.out.println("请输入a,b,c:");double a = input.nextDouble();double b = input.nextDouble();double c = input.nextDouble();QuadraticEquation q =new QuadraticEquation(a,b,c);if(q.getRoot1()==0 && q.getRoot2()==0){System.out.println("The equation has no roots");}else if(q.getRoot1()==q.getRoot2()){System.out.println(q.getRoot1());}else{System.out.println("root1 = "+q.getRoot1()+","+"root2 = "+q.getRoot2());}}
}QuadraticEquation.java
class QuadraticEquation
{private double a;private double b;private double c;public QuadraticEquation(double a,double b,double c){this.a = a;this.b = b;this.c = c;}public double getA() {return a;}public void setA(double a) {this.a = a;}public double getB() {return b;}public void setB(double b) {this.b = b;}public double getC() {return c;}public void setC(double c) {this.c = c;}public double getDiscriminant(){return b*b - 4*a*c;}public double getRoot1(){double root1 = (-b +Math.sqrt(this.getDiscriminant()))/(2*a);if(getDiscriminant() >= 0){return root1;}else{return 0;}}public double getRoot2(){double root2 = (-b - Math.sqrt(this.getDiscriminant()))/(2*a);if(getDiscriminant() >= 0){return root2;}else{return 0;}}
}