题目:
题解:
struct ListNode *getIntersectionNode(struct ListNode *headA, struct ListNode *headB) {if (headA == NULL || headB == NULL) {return NULL;}struct ListNode *pA = headA, *pB = headB;while (pA != pB) {pA = pA == NULL ? headB : pA->next;pB = pB == NULL ? headA : pB->next;}return pA;
}