numList = [1, 3, 5, 7, 9]
from itertools import combinationsfor i in range(1, len(numList) + 1):  # xrange will return the values 1,2,3,4 in this loopprint(list(combinations(numList, i)))输出：
[('1',), ('3',), ('5',), ('7',), ('9',)]
[('1', '3'), ('1', '5'), ('1', '7'), ('1', '9'), ('3', '5'), ('3', '7'), ('3', '9'), ('5', '7'), ('5', '9'), ('7', '9')]
[('1', '3', '5'), ('1', '3', '7'), ('1', '3', '9'), ('1', '5', '7'), ('1', '5', '9'), ('1', '7', '9'), ('3', '5', '7'), ('3', '5', '9'), ('3', '7', '9'), ('5', '7', '9')]
[('1', '3', '5', '7'), ('1', '3', '5', '9'), ('1', '3', '7', '9'), ('1', '5', '7', '9'), ('3', '5', '7', '9')]
[('1', '3', '5', '7', '9')]

多个列表获取全组合

1. 通过itertools类生成生成一个列表列表，其中包含两个列表之间的所有潜在组合

import itertoolslist1 = [1, 2, 3, 4, 5]
list2 = [5, 6, 7, 8, 9]
print(list(itertools.product(list1, list2)))
输出
[(1, 5), (1, 6), (1, 7), (1, 8), (1, 9), (2, 5), (2, 6), (2, 7), (2, 8), (2, 9), (3, 5), (3, 6), (3, 7), (3, 8), (3, 9), (4, 5), (4, 6), (4, 7), (4, 8), (4, 9), (5, 5), (5, 6), (5, 7), (5, 8), (5, 9)]

2. 使用列表生成器创建嵌套列表：

[[[x,y] for x in list1] for y in list2]
输出
[[[1, 5], [2, 5], [3, 5], [4, 5], [5, 5]], [[1, 6], [2, 6], [3, 6], [4, 6], [5, 6]], [[1, 7], [2, 7], [3, 7], [4, 7], [5, 7]], [[1, 8], [2, 8], [3, 8], [4, 8], [5, 8]], [[1, 9], [2, 9], [3, 9], [4, 9], [5, 9]]][[x,y] for x in list1 for y in list2]
[[1, 5], [1, 6], [1, 7], [1, 8], [1, 9], [2, 5], [2, 6], [2, 7], [2, 8], [2, 9], [3, 5], [3, 6], [3, 7], [3, 8], [3, 9], [4, 5], [4, 6], [4, 7], [4, 8], [4, 9], [5, 5], [5, 6], [5, 7], [5, 8], [5, 9]]

3. repeat第一个列表，permutate第二个列表和zip它们一起

 from itertools import permutations, repeata = [1, 2, 3]b = [4, 5, 6]print(list(list(zip(r, p)) for (r, p) in zip(repeat(a), permutations(b))))[[(1, 4), (2, 5), (3, 6)], [(1, 4), (2, 6), (3, 5)], [(1, 5), (2, 4), (3, 6)], [(1, 5), (2, 6), (3, 4)], [(1, 6), (2, 4), (3, 5)], [(1, 6), (2, 5), (3, 4)]]