package Game;import java.util.ArrayList;
import java.util.Collections;public class PokerGame01 {//牌盒//♥3 ♣3static ArrayList<String> list = new ArrayList<>();//静态代码块//特点：随着类的加载而在加载的，而且只执行一次。static {//准备牌// "♦", "♣", "♥", "♠"// "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K", "A", "2"String[] color = {"♦", "♣", "♥", "♠"};String[] number = {"3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K", "A", "2"};for (String c : color) {//c表示每一个牌的花色for (String n : number) {//n表示每一种牌号list.add(c + n);}}list.add("大王");list.add("小王");}public PokerGame01() {// 洗牌Collections.shuffle(list);// 发牌//定义4个集合，其中3个选手的牌,还要一个是用来存储地主多出来的3张牌ArrayList<String> dizhu = new ArrayList<>();ArrayList<String> player1 = new ArrayList<>();ArrayList<String> player2 = new ArrayList<>();ArrayList<String> player3 = new ArrayList<>();for (int i = 0; i < list.size(); i++) {//根据索引找到牌号，本质是要把前三张牌给地主String poke = list.get(i);//得到了第i张牌if (i <= 2) {dizhu.add(poke);//前三张给地主//依次轮流给3个选手发牌} else if (i % 3 == 0) {player1.add(poke);} else if (i % 3 == 1) {player2.add(poke);} else {player3.add(poke);}}//看牌lookpoke("张三",player1);lookpoke("李四",player2);lookpoke("王五",player3);}public void lookpoke(String name, ArrayList<String> list) {System.out.print(name + ": ");for (String poke : list) {//循环遍历得到每一张牌System.out.print(poke + " ");}System.out.println();}
}

排序的

package Game;import java.util.*;public class PokerGame02 {//牌盒//♥3 ♣3//键是序号，牌是值//此时只要把牌跟序号产生对应关系即可，不需要按照序号进行排序，所以只需HashMap即可static HashMap<Integer, String> hm = new HashMap<>();//用来存储序号的单列集合static ArrayList<Integer> list = new ArrayList<>();//静态代码块//特点：随着类的加载而在加载的，而且只执行一次。static {//准备牌// "♦", "♣", "♥", "♠"// "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K", "A", "2"String[] color = {"♦", "♣", "♥", "♠"};String[] number = {"3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K", "A", "2"};
/*{1=♦3, 2=♦4, 3=♦5, 4=♦6, 5=♦7, 6=♦8, 7=♦9, 8=♦10, 9=♦J, 10=♦Q, 11=♦K, 12=♦A, 13=♦2, 14=♣3,15=♣4, 16=♣5, 17=♣6, 18=♣7, 19=♣8, 20=♣9, 21=♣10, 22=♣J, 23=♣Q, 24=♣K, 25=♣A, 26=♣2, 27=♥3,28=♥4, 29=♥5, 30=♥6, 31=♥7, 32=♥8, 33=♥9, 34=♥10, 35=♥J, 36=♥Q, 37=♥K, 38=♥A, 39=♥2, 40=♠3,41=♠4, 42=♠5, 43=♠6, 44=♠7, 45=♠8, 46=♠9, 47=♠10, 48=♠J, 49=♠Q, 50=♠K, 51=♠A, 52=♠2}很明显可以看出没有按照顺序起好牌 应该先把数字一样的放在一起，而不是把花色一样的放在一起解决： 交换color和number即可
*///定义一个序号int num = 1;for (String n : number) {//n表示每一种牌号for (String c : color) {//c表示每一个牌的花色hm.put(num, c + n);list.add(num);num++;}}hm.put(num, "小王");list.add(num);num++;hm.put(num, "大王");list.add(num);}public PokerGame02() {// 洗牌Collections.shuffle(list);// 发牌/*
[39, 35, 7]
[28, 31, 15, 54, 14, 24, 3, 46, 43, 22, 37, 41, 29, 45, 16, 30, 48]
[33, 49, 11, 13, 38, 27, 25, 50, 20, 9, 1, 32, 19, 10, 44, 21, 40]
[53, 8, 34, 36, 17, 42, 5, 18, 2, 23, 12, 26, 4, 47, 6, 51, 52]
用ArrayList集合存储的索引是乱序的，我们本质是要根据序号也就是索引去到map集合里面找到牌，所以序号要有序*//*[5, 10, 34][2, 4, 7, 8, 13, 17, 18, 19, 20, 22, 27, 35, 37, 38, 39, 40, 42][1, 9, 14, 16, 23, 24, 28, 29, 30, 31, 32, 36, 41, 43, 46, 51, 52][3, 6, 11, 12, 15, 21, 25, 26, 33, 44, 45, 47, 48, 49, 50, 53, 54]*///定义4个集合，其中3个选手的牌,还要一个是用来存储地主多出来的3张牌TreeSet<Integer> dizhu = new TreeSet<>();TreeSet<Integer> player1 = new TreeSet<>();TreeSet<Integer> player2 = new TreeSet<>();TreeSet<Integer> player3 = new TreeSet<>();//获取所有的键，把这些键放入单列集合当中// Set<Integer> integers1 = hm.keySet();for (int i = 0; i < list.size(); i++) {//根据索引找到牌的序号，本质是要把前三张牌的序号给地主int number = list.get(i);  //得到了第i张牌的序号if (i <= 2) {dizhu.add(number); //前三张牌的序号给地主// integers1.add(poke);//依次轮流给3个选手发牌} else if (i % 3 == 0) {player1.add(number);} else if (i % 3 == 1) {player2.add(number);} else {player3.add(number);}}//看牌lookpoke("底牌",dizhu);lookpoke("张三",player1);lookpoke("李四",player2);lookpoke("王五",player3);// look("赵六",integers1);}/** 参数一：玩家的名字* 参数二：牌的序号* */public void lookpoke(String name, TreeSet<Integer> ts) {System.out.print(name + ": ");for (int num : ts) {//num就是代表的是序号，遍历方法1 通过键找值的方式遍历map集合//遍历TreeSet集合得到每一个序号，再拿着序号到Map集合中去找真正的牌String poke = hm.get(num);//通过键（序号）拿到了每一张牌（值）System.out.print(poke + " ");}System.out.println();}//遍历单列集合，得到每一个键;/* public void look(String name, Set<Integer> key) {System.out.print(name+": ");//遍历单列集合，得到每一个键for (int num : key) {//num代表就是序号//通过序号（键）去找到map集合里面的值String value = hm.get(num);System.out.print(value+" ");}System.out.println();}*/
}

package Game;import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.HashMap;public class PokerGame03 {//牌盒//♥3 ♣3static ArrayList<String> list = new ArrayList<>();//创建一个集合，用来添加牌的价值,牌号是键,价值是值static HashMap<String, Integer> hm = new HashMap<>();//静态代码块//特点：随着类的加载而在加载的，而且只执行一次。static {//准备牌// "♦", "♣", "♥", "♠"// "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K", "A", "2"String[] color = {"♦", "♣", "♥", "♠"};String[] number = {"3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K", "A", "2"};for (String c : color) {//c表示每一个牌的花色for (String n : number) {//n表示每一种牌号list.add(c + n);}}list.add(" 大王");list.add(" 小王");//指定牌的价值//牌上的数字到Map集合中判断是否存在//存在，获取价值//不存在，本身的数字就是价值hm.put("J", 11);hm.put("Q", 12);hm.put("K", 13);hm.put("A", 14);hm.put("2", 15);hm.put("小王", 50);hm.put("大王", 100);}public PokerGame03() {// 洗牌Collections.shuffle(list);// 发牌//定义4个集合，其中3个选手的牌,还要一个是用来存储地主多出来的3张牌ArrayList<String> dizhu = new ArrayList<>();ArrayList<String> player1 = new ArrayList<>();ArrayList<String> player2 = new ArrayList<>();ArrayList<String> player3 = new ArrayList<>();for (int i = 0; i < list.size(); i++) {//根据索引找到牌号，本质是要把前三张牌给地主String poke = list.get(i);//得到了第i张牌if (i <= 2) {dizhu.add(poke);//前三张给地主//依次轮流给3个选手发牌} else if (i % 3 == 0) {player1.add(poke);} else if (i % 3 == 1) {player2.add(poke);} else {player3.add(poke);}}//排序order(dizhu);order(player1);order(player2);order(player3);//看牌lookpoke("张三",player1);lookpoke("李四",player2);lookpoke("王五",player3);lookpoke("底牌",dizhu);}//利用牌的价值进行排序//参数：集合//♥5 ♥3 ♥6 ♥7 ♥9private void order(ArrayList<String> list) {Collections.sort(list, new Comparator<String>() {@Overridepublic int compare(String o1, String o2) {//o1：表示当前要插入到有序序列中的牌//o2：表示已经在有序序列中存在的牌//负数：o1小 插入到前面//正数：o1大 插入到后面//0：o1的数字跟o2的数字是一样的，需要按照花色再次排序//1.计算o1的花色和价值  String color1 = o1.substring(0, 1);;//♥3中的♥//价值int value1 = getValue(o1);//2.计算o2的花色和价值String color2= o1.substring(0, 1);//♥3中的♥//价值int value2 = getValue(o2);//3.比较o1和o2的价值    ♥3  ♠3int i = value1 - value2;return i == 0 ? color1.compareTo(color2) : i;}});}//计算牌的价值//参数：牌//返回值：价值public int getValue(String poker) {  //♥3//获取牌上的数字String number = poker.substring(1);//比如♥3中的3//把这里截取出来的结果，让这个结果再Map集合中存在/*hm.put("J", 11);hm.put("Q", 12);hm.put("K", 13);hm.put("A", 14);hm.put("2", 15);hm.put("小王", 50);hm.put("大王", 100);*///如果不存在类型转换 如"3"的价值就值3//如果存在在map集合里面拿出对应的价值即可//拿着数字到map集合中判断是否存在if (hm.containsKey(number)) {//存在，获取价值return hm.get(number);} else {//不存在，类型转换return Integer.parseInt(number);}}public void lookpoke(String name, ArrayList<String> list) {System.out.print(name + ": ");for (String poke : list) {//循环遍历得到每一张牌System.out.print(poke + " ");}System.out.println();}
}