Hive SQL业务场景：连续5天涨幅超过5%股票

一、需求描述

现有一张股票价格表 dwd_stock_trade_dtl 有3个字段分别是：

股票代码(stock_code),

日期(trade_date)，

收盘价格(closing_price) 。

请找出满足连续5天以上（含）每天上涨超过5%的股票，并给出连续满足天数及开始和结束日期。

备注：不考虑停牌或其他情况，仅仅关注每天连续5天上涨超过5%的股票。

二、数据准备

1、建Hive表

DROP TABLE IF EXISTS dwd_stock_trade_dtl;
CREATE TABLE IF NOT EXISTS dwd_stock_trade_dtl (  stock_code STRING,  trade_date DATE,  closing_price DECIMAL(10,2)  
)  
ROW FORMAT DELIMITED  
FIELDS TERMINATED BY ','  
STORED AS TEXTFILE;

2、插入测试数据

--样例数据插入
INSERT INTO TABLE dwd_stock_trade_dtl
VALUES 
('AAPP', '2024-02-26', 100.00),
('RAAB', '2024-02-27', 105.00),
('RAAB', '2024-02-28', 110.25),
('RAAB', '2024-03-01', 115.78),
('RAAB', '2024-03-02', 121.59),
('RAAB', '2024-03-03', 128.73),
('RAAB', '2024-03-04', 137.00),
('RAAB', '2024-03-05', 144.67),
('RAAB', '2024-03-06', 147.64),
('EWXN', '2024-02-26', 2000.00),
('EWXN', '2024-02-27', 2100.00),
('EWXN', '2024-02-28', 2205.00),
('EWXN', '2024-03-01', 2313.25),
('EWXN', '2024-03-02', 2431.01),
('EWXN', '2024-03-03', 2547.56),
('EWXN', '2024-03-04', 2680.19),
('EWXN', '2024-03-05', 2814.20),
('EWXN', '2024-03-06', 2955.91);

三、需求分析

用lag函数列出前一天的交易价格

算出每日涨幅：（今天交易价格 / 前一天交易价格）- 1

判断是否满足涨幅大于5%，满足打个flag

用row_number 函数算出连续

最后用min，max，count 函数求出连续上涨的最小日期，最大日期和天数

四、需求实现

1、用lag函数列出前一天的交易价格并算出每日涨幅：（今天交易价格 / 前一天交易价格）- 1

SELECT stock_code,trade_date,closing_price, -- -- 交易价格LAG(closing_price) OVER (PARTITION BY stock_code ORDER BY trade_date ASC) as a_closing_price, -- 前一天交易价格(closing_price / LAG(closing_price) OVER (PARTITION BY stock_code ORDER BY trade_date ASC) ) - 1 AS daily_return -- 涨幅
FROM dwd_stock_trade_dtl;

2、判断是否满足涨幅大于5%，满足标记1，不满足0

SELECT stock_code,trade_date, closing_price, -- -- 交易价格LAG(closing_price) OVER (PARTITION BY stock_code ORDER BY trade_date ASC) as a_closing_price, -- 前一天交易价格(closing_price / LAG(closing_price) OVER (PARTITION BY stock_code ORDER BY trade_date ASC) ) - 1 AS daily_return, -- 涨幅if(closing_price / LAG(closing_price) OVER (PARTITION BY stock_code ORDER BY trade_date ASC) - 1 >= 0.05, 1,0) AS flag
FROM  dwd_stock_trade_dtl

3、用row_number 函数算出每只股票日期排序，和每只股票是否满足条件下的日期排序，然后相减，相同则满足连续

SELECT stock_code, trade_date, flag, row_number() OVER (PARTITION BY stock_code ORDER BY trade_date ASC) AS a_rn,row_number() OVER (PARTITION BY stock_code, flag ORDER BY trade_date ASC) AS flag_rn,row_number() OVER (PARTITION BY stock_code ORDER BY trade_date ASC) - row_number() OVER (PARTITION BY stock_code, flag ORDER BY trade_date ASC) AS diff_rn
FROM (SELECT stock_code, trade_date, if(closing_price / LAG(closing_price) OVER (PARTITION BY stock_code ORDER BY trade_date ASC) - 1 >= 0.05, 1, 0) AS flagFROM dwd_stock_trade_dtl) a
ORDER BY stock_code, trade_date

4、最后，求出连续涨幅超过5%的开始日期，结束日期，天数。

SELECT stock_code, min(trade_date) AS min_trade_date, -- 开始日期max(trade_date) AS max_trade_date, -- 结束日期count(1) AS day_cnt -- 天数
FROM (SELECT stock_code, trade_date, flag, row_number() OVER (PARTITION BY stock_code ORDER BY trade_date ASC) AS a_rn, row_number() OVER (PARTITION BY stock_code, flag ORDER BY trade_date ASC) AS flag_rn, row_number() OVER (PARTITION BY stock_code ORDER BY trade_date ASC) - row_number() OVER (PARTITION BY stock_code, flag ORDER BY trade_date ASC) AS diff_rnFROM (SELECT stock_code, trade_date, if(closing_price / LAG(closing_price) OVER (PARTITION BY stock_code ORDER BY trade_date ASC) - 1 >= 0.05, 1, 0) AS flagFROM dwd_stock_trade_dtl) a) b
WHERE flag = 1
GROUP BY stock_code, diff_rn
HAVING count(1) >= 5