题目：

题解：

func isInterleave(s1 string, s2 string, s3 string) bool {n, m, t := len(s1), len(s2), len(s3)if (n + m) != t {return false}f := make([]bool, m + 1)f[0] = truefor i := 0; i <= n; i++ {for j := 0; j <= m; j++ {p := i + j - 1if i > 0 {f[j] = f[j] && s1[i-1] == s3[p]}if j > 0 {f[j] = f[j] || f[j-1] && s2[j-1] == s3[p]}}}return f[m]
}