2023每日刷题（九十四）
Leetcode—29. 两数相除
叛逆期实现代码
class Solution {
public:int divide(int dividend, int divisor) {if(dividend == INT_MIN && divisor == -1) {return INT_MAX;} return dividend / divisor;}
};
运行结果
倍增算法实现代码
class Solution {
public:int divide(int dividend, int divisor) {if(dividend == INT_MIN && divisor == -1) {return INT_MAX;} if(dividend == INT_MIN && divisor == 1) {return INT_MIN;}long long res = 0;long long a = labs((long long)dividend);long long b = labs((long long)divisor);if(a < b) {return 0;}while(a - b >= 0) {long long x = 0;while(a - (b << 1 << x) >= 0) {x++;}res += 1 << x;a -= b << x;}if((dividend > 0) ^ (divisor > 0)) {res = -res;}return res > INT_MAX ? INT_MAX: res;}
};
运行结果
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