如果搜索多个单词，则创建一个集合是有意义的：print(set(brown_sents).intersection(zip(repeat(most_ambiguous_word),

word_class_dict[most_ambiguous_word])))

输出{('word2', 'wordclass2'), ('word2', 'wordclass3')}

要理解它的作用，请将脚本保存到一个文件中，例如search-word.py，然后运行：$ python -i search-word.py

它显示Python提示符：>>>

您可以尝试单个表达式来查看它们的作用，例如：>>> zip(repeat('a'), [1,2,3])

[('a', 1), ('a', 2), ('a', 3)]

>>> set('abcaadeff')

set(['a', 'c', 'b', 'e', 'd', 'f'])

>>> set('abcaadeff').intersection('abc')

set(['a', 'c', 'b'])

查看帮助：>>> help(zip)

Help on built-in function zip in module __builtin__:

zip(...)

zip(seq1 [, seq2 [...]]) -> [(seq1[0], seq2[0] ...), (...)]

Return a list of tuples, where each tuple contains the i-th element

from each of the argument sequences. The returned list is truncated

in length to the length of the shortest argument sequence.

按q退出。如果个别帮助信息不清晰：>>> help(repeat)

Help on class repeat in module itertools:

class repeat(__builtin__.object)

| repeat(element [,times]) -> create an iterator which returns the element

| for the specified number of times. If not specified, returns the element

| endlessly.

...[snip]...

请尝试查看模块的联机帮助：>>> module = 'itertools'

>>> import webbrowser

>>> webbrowser.open('http://docs.python.org/library/' + module)

找到^{}函数。在

简而言之：阅读文档，在提示下尝试一些代码，重复。如果你卡住了，ask question。在