map() 是python的内置函数，会根据提供的函数对指定序列做映射。

对可迭代函数*iterables中的每个元素应用func方法，将结果作为迭代器对象返回。

注意：map()函数返回的是一个新的迭代器对象，不会改变原有对象 

map()用法
class map(object)|  map(func, *iterables) --> map object|  |  Make an iterator that computes the function using arguments from|  each of the iterables.  Stops when the shortest iterable is exhausted.|  |  Methods defined here:|  |  __getattribute__(self, name, /)|      Return getattr(self, name).|  |  __iter__(self, /)|      Implement iter(self).|  |  __next__(self, /)|      Implement next(self).|  |  __reduce__(...)|      Return state information for pickling.|  |  ----------------------------------------------------------------------|  Static methods defined here:|  |  __new__(*args, **kwargs) from builtins.type|      Create and return a new object.  See help(type) for accurate signature.

案例一
# 计算平方数
def square(x):return x * x
obj = map(square, [1, 2, 3])
print(type(obj), obj)
print(list(obj))C:\Users\admin\AppData\Local\Programs\Python\Python37\python.exe C:/Users/admin/Desktop/AutoTest/Test/test/test_01/test_01.py
<class 'map'> <map object at 0x0000023BC9B59D88>
[1, 4, 9]Process finished with exit code 0

案例二
# 使用 lambda 匿名函数计算平方数
square = map(lambda x: x ** 2, [1, 2, 3, 4, 5])
print(square, list(square))C:\Users\admin\AppData\Local\Programs\Python\Python37\python.exe C:/Users/admin/Desktop/AutoTest/Test/test/test_01/test_01.py
<map object at 0x0000015705389D88> [1, 4, 9, 16, 25]Process finished with exit code 0

案例三
# 按首字母大写，后字母小写规则显示名字
name_list = ['chengzi', 'JACK', 'wangLi']
def format_name(name_list):return name_list[0:1].upper()+name_list[1:].lower()
obj = map(format_name, name_list)
print(obj, list(obj))C:\Users\admin\AppData\Local\Programs\Python\Python37\python.exe C:/Users/admin/Desktop/AutoTest/Test/test/test_01/test_01.py
<map object at 0x000001FCF0D76708> ['Chengzi', 'Jack', 'Wangli']Process finished with exit code 0