您可以在代码中添加更多行来执行此操作：

首先创建两个带有字符的列表，一个带有要映射的整数，然后从那些创建dict：

list_1=["A","B","C","D","E","F"]

list_2=[10,11,12,13,14,15]

new_dict={i:j for i,j in zip(list_1,list_2)}现在在最后一行代码中添加这些行，以检查输入的最后一位是否在dict中，然后获取该值的键。

新=余数[：]

for i in new:

for j,k in new_dict.items():

if k==i:

print("{}{}".format(j,''.join(str(x) for x in remainders[::-1][1:])))完成。

完整代码：

list_1=["A","B","C","D","E","F"]

list_2=[10,11,12,13,14,15]

new_dict={i:j for i,j in zip(list_1,list_2)}

number = input("enter a number: ")

number = int(number)

remainders = list()

while number>0:

remainders.append(int(number % 16))

number//=16

new=remainders[:]

for i in new:

for j,k in new_dict.items():

if k==i:

print("{}{}".format(j,''.join(str(x) for x in remainders[::-1][1:])))运行时间：

enter a number: 3877

F25