1, 获取每天的零点
DateTime dt=new DateTime().withMillisOfDay(0);
System.out.println(dt.toString("yyyy-MM-dd HH:mm:ss"));//结果
2016-09-09 00:00:00
2, 在每天的6:30处理一些东西
DateTime dt=new DateTime().withHourOfDay(6).withMinuteOfHour(30).withSecondOfMinute(0);
System.out.println(dt.toString("yyyy-MM-dd HH:mm:ss"));
//结果
2016-09-09 06:30:00
3, 在每月的7号的6:30处理一些东西
DateTime dt=new DateTime().withDayOfMonth(7).withHourOfDay(6).withMinuteOfHour(30).withSecondOfMinute(0);
System.out.println(dt.toString("yyyy-MM-dd HH:mm:ss"));
//结果
2016-09-07 06:30:00
4, 在每年的8月的7号的6:30处理一些东西
DateTime dt=new DateTime().withMonthOfYear(8).withDayOfMonth(7).withHourOfDay(6).withMinuteOfHour(30).withSecondOfMinute(0);
System.out.println(dt.toString("yyyy-MM-dd HH:mm:ss"));
//结果
2016-08-07 06:30:00
5, 获取每个月的第一天和最后一天
DateTime dateTime=new DateTime();
System.out.println(dateTime.dayOfMonth().withMinimumValue().dayOfMonth().get());
System.out.println(dateTime.dayOfMonth().withMaximumValue().dayOfMonth().get());
//结果
1
30
6, 获取每天的零点的下一天零点
DateTime dt=new DateTime().withMillisOfDay(0).plusDays(1);
System.out.println(dt.toString("yyyy-MM-dd HH:mm:ss"));
7, 获取日期差
DateTime start=new DateTime(2015,5,4,12,20);DateTime start=new DateTime(2015,5,4,12,20);DateTime end=new DateTime(2015,5,6,3,10);Period period=new Period(start,end);System.out.println("month:"+period.getMonths());System.out.println("days:"+period.getDays());System.out.println("hours:"+period.getHours());System.out.println("minutes:"+period.getMinutes());System.out.println("second:"+period.getSeconds());
//结果
month:0
days:1
hours:14
minutes:50
second:0
8, 单独获取天,小时,分钟,秒
DateTime start=new DateTime(2015,5,4,12,20);DateTime end =new DateTime(2015,5,5,12,00);System.out.println(Days.daysBetween(start,end).getDays());System.out.println(Hours.hoursBetween(start,end).getHours());System.out.println(Minutes.minutesBetween(start,end).getMinutes());System.out.println(Seconds.secondsBetween(start,end));
9, 时间判断是否在某个范围以及获取时间差的毫秒
DateTime start=new DateTime(2015,5,4,12,20);DateTime end =new DateTime(2015,5,5,12,00);Interval interval=new Interval(start,end);System.out.println(interval.contains(new DateTime(2015,5,5,11,00)));Duration duration=new Duration(start,end);System.out.println(duration.getStandardHours());
官网连接
http://www.joda.org/joda-time/userguide.html