PHP | 检查字符串中是否存在特定的单词/子字符串

Given a string and a word/substring, and we have to check whether a given word/substring exists in the string.

给定一个字符串和一个单词/子字符串，我们必须检查字符串中是否存在给定的单词/子字符串。

PHP code to check substring in the string

PHP代码检查字符串中的子字符串

<?php
//function  to find the substring Position
//if substring exists in the string
function findMyWord($s, $w) {
if (strpos($s, $w) !== false) {
echo 'String contains ' . $w . '<br/>';
} else {
echo 'String does not contain ' . $w . '<br/>';
}
}
//Run the function
findMyWord('The Quick brown fox jumps right over the Lazy Dog', 'fox');
findMyWord('The Quick brown fox jumps right over the Lazy Dog', 'hello');
?>

Output

输出量

String contains fox
String does not contain hello

Explanation:

说明：

To check if a string contains a word (or substring) we use the PHP strpos() function. We check if the word ($w) is present in the String ($s). Since strpos() also returns non-Boolean value which evaluates to false, We have to check the condition to be explicit !== false (Not equal to False) Which ensures that we get a more reliable response.

要检查字符串是否包含单词(或子字符串)，我们使用PHP strpos()函数。我们检查单词( $ w )是否存在于字符串( $ s )中。由于strpos()还返回非布尔值，该值的计算结果为false，因此我们必须检查条件是否为显式！== false(不等于False)，这确保我们获得更可靠的响应。