航空机票预订c#代码_航空公司座位预订问题的C ++程序

航空机票预订c#代码

Problem statement: Write a program to assign passengers seats in an airplane. Assume a small airplane with seat numbering as follows:

问题陈述：编写一个程序来分配飞机上的乘客座位。假设小型飞机的座位编号如下：

    1 A B C D
2 A B C D
3 A B C D
4 A B C D
5 A B C D
6 A B C D
7 A B C D

The program should display the seat pattern, with an ‘X’ marking the seats already assigned. After displaying the seats available, the program prompts the seat desired, the user types in a seat, and then the display of available seats is updated. This continues until all seats are filled or until the user signals that the program should end. If the user types in a seat that is already assigned, the program should say that the seat is occupied and ask for another choice.

程序应显示座位模式，并带有“ X”标记已分配的座位。在显示可用座位之后，程序会提示所需的座位，用户键入座位，然后更新可用座位的显示。这一直持续到所有座位都装满或用户发出程序结束的信号为止。如果用户键入已经分配的座位，则程序应说明该座位已被占用，并要求其他选择。

Input Example:

输入示例：

For example, after seats 1A, 2B, and 4C are taken, the display should look like:

例如，在坐下了座位1A，2B和4C之后，显示屏应如下所示：

    1 X B C D
2 A X C D
3 A B C D
4 A B X D
5 A B C D
6 A B C D
7 A B C D

Solution

解

The whole problem can be implemented with help of 4 major functions:

可以通过以下四个主要功能来实现整个问题：

getData()
getData()
display()
显示()
check()
check()
update()
update()

The entire problem is discussed dividing into parts focusing on functional modularity.

讨论了整个问题，分为针对功能模块化的部分。

1. Initialize a 2-D array to represent the seat matrix

1.初始化一个二维数组以表示座位矩阵

A 2-D character array is used to represent the seat matrix where the first column have the row number of each seat & the rest of the columns have four seat A,B,C,D respectively. Thus it’s a 7X5 2-D array to represent the airplane seat matrix which looks like following:

2-D字符数组用于表示席位矩阵，其中第一列具有每个席位的行号，其余列分别具有四个席位A，B，C，D。因此，它是一个7X5二维数组，表示飞机座椅矩阵，如下所示：

2. Take user input for seat no

2.接受用户输入的座位号

User is requested to input the desired seat no by giving corresponding no of seat. Like a valid seat no is 1A, 3C, 7D and so on, whereas, an invalid seat request can be 6F, 0B so on.

要求用户通过提供相应的座位号来输入所需的座位号。像有效席位一样，no是1A，3C，7D等，而无效席位请求可以是6F，0B等。

The input is taken by our function getData() which takes user input & returns the string.

输入由我们的函数getData()获得 ，该函数接受用户输入并返回字符串。

3. Check the seat no request (check() )

3.检查座位无要求(check())

Our major function for this problem is to check the validity of the seat request & update seat matrix status as per request.

我们针对该问题的主要功能是检查座位请求的有效性并根据请求更新座位矩阵状态。

Firstly it checks whether the user input is in the range 1A to 7D or not. If user input is out of range a prompt out "invalid request" & continue for further request.
首先，它检查用户输入是否在1A到7D范围内。如果用户输入超出范围，则提示“无效请求”并继续进行进一步的请求。
Check whether user input is 'N' or not. If it's 'N' then user wants to end the program. Terminate.
检查用户输入是否为“ N” 。如果为“ N”，则用户要结束程序。终止。
if seat request is valid but already occupied
如果座位请求有效但已被占用

Then prompt a message stating “It’s already occupied”
然后提示信息“已被占用”

This checking can be done by founding the 2-D array row & column index for the corresponding seat.
可以通过找到相应座位的二维数组行和列索引来完成此检查。

Let,
让，

row_index=r&column_index=c
If(seat_matrix[row_index][column_index]==’X’)
row_index = r＆column_index = c
如果(seat_matrix [row_index] [column_index] =='X')

Seat is occupied.
座位已满。
ELSE seat request is a valid one and not occupied still
ELSE座位请求是有效的，尚未占用

Update()
更新()

4. Update the valid entry

4.更新有效条目

If the request is to update the valid seat we simple change its value to 'X'. It can be done by finding row & column index and updating the value of seat_matrix at that location to 'X'.

如果请求更新有效席位，我们只需将其值更改为'X'即可 。可以通过查找行和列索引并将该位置的seat_matrix值更新为'X'来完成 。

5. Special function to check whether all seats are occupied

5.特殊功能，检查是否所有座位都被占用

The program also need to be terminated when all seats are occupied. Thus every time we keep a checking whether all the entry of seat_matrix is 'X' or not.

当所有座位都坐满时，还需要终止该程序。因此，每次我们都检查一下seat_matrix的所有条目是否为“ X” 。

航空公司座位预订问题的C ++实现 (C++ implementation for Airline Seat Reservation Problem)

#include <bits/stdc++.h>
using namespace std;
// to check whether all sits are occupied or not
int allOccupied(char arr[7][5]){ 
int count=0;
for(int i=0;i<7;i++){
for(int j=1;j<5;j++)
if(arr[i][j]=='X')
count++;
}
if(count==28)
return 1;
return 0;
}
//to display the sits
void display(char arr[7][5]){ 
for(int i=0;i<7;i++){
for(int j=0;j<5;j++){
cout<<arr[i][j]<<" ";
}
cout<<endl;
}
return;
}
//take user data
string getData(){ 
string p;
cout<<"enter valid seat no to check(like 1B) or N to end: ";
cin>>p;
return p;
}
//update sit status
void update(char arr[7][5],int row,int col){ 
cout<<"congrats, your seat is valid. Reserved for you\n";
cout<<"updated seat status..........\n";
arr[row][col]='X';
}
//checking whether user request for 
//his sit no can be processed or not
int check(char arr[7][5],string s){ 
//if user input is not in the range 1A to 7D
if(s[0]>'7' || s[0]<'1' || s[1]>'D' || s[1]<'A'){ 
cout<<"invalid seat no\n"; //invalid sit no
return 0;
}
int row=-1,col=-1;
//find the row no of the user sit
for(int i=0;i<7;i++){
if(arr[i][0]==s[0])
row=i;
}
//find the column no of user sit
for(int j=0;j<5;j++){
if(arr[row][j]==s[1])
col=j;
}
//check whether sit is already occupied or not.
if(col==-1){
cout<<"Seat is already occupied\n";
return 0;
}
else{
//if it's a valid sit & not occupied, 
//process the requested & update the sit as occupied 
update(arr,row,col);   
}
return 1;
} 
void airline(char arr[7][5]){
// user can stop process by pressing 'N'
cout<<"enter N if you are done!\n"; 
string s;
// continue if not interrepted by user or 
//there is valid sit in unoccupied state
while(true){ 
s=getData(); //get user input
//if user input is to stop the process
if(s[0]=='N') 
break; // break
//process the request & check according to
if(check(arr,s)) 
display(arr);
if(allOccupied(arr)){ //if all sits are occupied
cout<<"sorry, no more seats left!!!!!!!!!!1..."<<endl;
break; //break
}
}
cout<<"Thanks, that's all"<<endl; //end of program
}
int main()
{
//2-D array for storing sit number
char arr[7][5]; 
for(int i=0;i<7;i++){
//forst column is row number
arr[i][0]=i+1+'0';
for(int j=1;j<5;j++){
//to represent sit number A,B,C,D respectively
arr[i][j]='A'+j-1; 
}
}
cout<<"initial seat arrangements........\n";
display(arr);
airline(arr); //airline function
return 0;
}

Output

输出量

initial seat arrangements........
1 A B C D
2 A B C D
3 A B C D
4 A B C D
5 A B C D
6 A B C D
7 A B C D
enter N if you are done!
enter valid seat no to check(like 1B) or N to end: 2B 
congrats, your seat is valid. Reserved for you  
updated seat status.......... 
1 A B C D
2 A X C D
3 A B C D
4 A B C D
5 A B C D
6 A B C D
7 A B C D
enter valid seat no to check(like 1B) or N to end: 3C 
congrats, your seat is valid. Reserved for you  
updated seat status.......... 
1 A B C D
2 A X C D
3 A B X D
4 A B C D
5 A B C D
6 A B C D
7 A B C D
enter valid seat no to check(like 1B) or N to end: 2B 
Seat is already occupied
enter valid seat no to check(like 1B) or N to end: 7E 
invalid seat no
enter valid seat no to check(like 1B) or N to end: 7C 
congrats, your seat is valid. Reserved for you  
updated seat status.......... 
1 A B C D
2 A X C D
3 A B X D
4 A B C D
5 A B C D
6 A B C D
7 A B X D
enter valid seat no to check(like 1B) or N to end: N  
Thanks, that's all