题干：
Problem Statement
We ask you to select some number of positive integers, and calculate the sum of them.
It is allowed to select as many integers as you like, and as large integers as you wish. You have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.
Your objective is to make the sum congruent to C modulo B. Determine whether this is possible.
If the objective is achievable, print YES. Otherwise, print NO.
Constraints
- 1≤A≤100
- 1≤B≤100
- 0≤C<B
Input
Input is given from Standard Input in the following format:
A B C
Output
Print YES or NO.
Sample Input 1
7 5 1
Sample Output 1
YES
For example, if you select 7 and 14, the sum 21 is congruent to 1 modulo 5.
Sample Input 2
2 2 1
Sample Output 2
NO
The sum of even numbers, no matter how many, is never odd.
Sample Input 3
1 100 97
Sample Output 3
YES
You can select 97, since you may select multiples of 1, that is, all integers.
Sample Input 4
40 98 58
Sample Output 4
YES
Sample Input 5
77 42 36
Sample Output 5
NO
解题报告：
AC代码1：（找规律）
AC代码2：（自己写）
#include<cstdio>
#include<queue>
#include<string>
#include<cstring>
#include<cmath>
#include<map>
#include<iostream>
#include<algorithm>
#define ll long long
const ll mod = 1e9+7;
using namespace std;
int a,b,c;
int main()
{while(~scanf("%d%d%d",&a,&b,&c)) {int flag = 0;for(int k = 1; k<=10000005; k++) {if((b*k+c) % a == 0) {printf("YES\n");flag = 1;break;}}if(!flag) printf("NO\n");}return 0 ;
}
