toj 3616 Add number (没想到啊~~)

Add number

时间限制(普通/Java):1000MS/3000MS 运行内存限制:65536KByte
总提交: 60 测试通过: 21

描述

Employees of Baidu like to play a game called Making Numbers. It goes like this: there are two players in the game, one is called little A, the other little B. There are some cards with a number on each one of them, little A chooses a number X from 1 to N randomly, while little B has to choose some cards, the sum of which equals X. Now there are already M cards with numbers, and K blank cards. At the beginning of the game, little B is allowed to write numbers on the blank cards. Now little B wants to know, if it is possible to write some numbers that will assure him of the victory, that is to say, if it is possible for him to make up any number from 1 to N with the cards.

输入

The input consists of several test cases. The first line is an integer T,

The first line of each case shows 3 numbers, N M K, the next line follows M numbers that are already written on M cards. 1<=N<=99999999,0<=M<=19,1<=K<=19 and the numbers on M cards are above 0, smaller than or equals N, in non-descending order.

输出

If little B can make it, output "YES", else output "NO".

样例输入

3
15 0 412 3 2
3 3 3
13 3 2
3 3 3

样例输出

YES
YES
NO

题目来源

第四届北京邮电大学程序设计竞赛 2010

 1 #include <stdio.h>
 2 int main()
 3 {
 4     int T;
 5     scanf("%d", &T);
 6     while(T--){
 7         int n, m, k;
 8         scanf("%d %d %d", &n, &m, &k);
 9         int a[100];
10         for(int i = 0; i < m; i++){
11             scanf("%d", a+i);
12         }
13         int sum = 0;
14         int tmp = 1;
15         while(sum < n && k >= 0){
16             bool flag = false;
17             for(int i = 0; i < m; i++){
18                 if(a[i] && a[i] <= tmp){
19                     sum += a[i];
20                     a[i] = 0;
21                     flag = true;
22                 }
23             }
24             if(!flag){
25                 sum += tmp;
26                 k--;
27             }
28             tmp = sum + 1;
29         }
30         if(k >= 0 && sum >= n){
31             puts("YES");
32         }
33         else{
34             puts("NO");
35         }
36     }
37     return 0;
38 }