Deduction Queries
用并查集维护前缀的关系, 在同一个联通块内两两之间的异或值都是已知的。
每个点再维护一个和它当前父亲的异或值, 压缩路径的时候更新一下就好了。
#include<bits/stdc++.h> #define LL long long #define LD long double #define ull unsigned long long #define fi first #define se second #define mk make_pair #define PLL pair<LL, LL> #define PLI pair<LL, int> #define PII pair<int, int> #define SZ(x) ((int)x.size()) #define ALL(x) (x).begin(), (x).end() #define fio ios::sync_with_stdio(false); cin.tie(0);using namespace std;const int N = 5e5 + 7; const int inf = 0x3f3f3f3f; const LL INF = 0x3f3f3f3f3f3f3f3f; const int mod = 1e9 + 7; const double eps = 1e-8; const double PI = acos(-1);template<class T, class S> inline void add(T& a, S b) {a += b; if(a >= mod) a -= mod;} template<class T, class S> inline void sub(T& a, S b) {a -= b; if(a < 0) a += mod;} template<class T, class S> inline bool chkmax(T& a, S b) {return a < b ? a = b, true : false;} template<class T, class S> inline bool chkmin(T& a, S b) {return a > b ? a = b, true : false;}int q, tot; map<int, int> Map;int xorWithFa[N]; int fa[N];int getRoot(int x) {if(x == fa[x]) return x;int preFa = fa[x];int nowFa = getRoot(fa[x]);xorWithFa[x] ^= xorWithFa[preFa];return fa[x] = nowFa; }int main() {for(int i = 1; i < N; i++) fa[i] = i;scanf("%d", &q);int ans = 0;while(q--) {int op; scanf("%d", &op);if(op == 1) {int l, r, x;scanf("%d%d%d", &l, &r, &x);l ^= ans; r ^= ans; x ^= ans;if(l > r) swap(l, r);l--;if(Map.find(l) == Map.end()) Map[l] = ++tot;if(Map.find(r) == Map.end()) Map[r] = ++tot;l = Map[l]; r = Map[r];int fal = getRoot(l);int far = getRoot(r);if(fal != far) {int xor1 = xorWithFa[l];int xor2 = xorWithFa[r];fa[far] = fal;xorWithFa[far] = xor1 ^ xor2 ^ x;}} else {int l, r;scanf("%d%d", &l, &r);l ^= ans; r ^= ans;if(l > r) swap(l, r);l--;if(Map.find(l) == Map.end() || Map.find(r) == Map.end()) {puts("-1");ans = 1;} else {l = Map[l]; r = Map[r];int fal = getRoot(l);int far = getRoot(r);if(fal != far) {puts("-1");ans = 1;} else {ans = xorWithFa[l] ^ xorWithFa[r];printf("%d\n", ans);}}}}return 0; }/* */