创建一个循环链表，并将这个循环链表拆分成为两个循环链表的示例程序，将以下代码保存到一个源文件中：split_circular_linked_list.c， 如下所示 –
#include #include struct node { int data; struct node *next; }; struct node *even = NULL; struct node *odd = NULL; struct node *list = NULL; //Create Linked List void insert(int data) { // Allocate memory for new node; struct node *link = (struct node*) malloc(sizeof(struct node)); struct node *current; link->data = data; link->next = NULL; if (list == NULL) { list = link; list->next = link; return; } current = list; while (current->next != list) current = current->next; // Insert link at the end of the list current->next = link; link->next = list; } void display(struct node *head) { struct node *ptr = head; printf("[head] =>"); //start from the beginning while (ptr->next != head) { printf(" %d =>", ptr->data); ptr = ptr->next; } printf(" %d =>", ptr->data); printf(" [head]n"); } void split_list() { int count = 0; // Allocate memory for new node; struct node *list1; struct node *link; struct node *current; list1 = list; while (list1->next != list) { struct node *link = (struct node*) malloc(sizeof(struct node)); link->data = list1->data; link->next = NULL; if (list1->data % 2 == 0) { if (even == NULL) { even = link; even->next = link; list1 = list1->next; continue; } else { current = even; while (current->next != even) { current = current->next; } // Insert link at the end of the list current->next = link; link->next = even; } list1 = list1->next; } else { if (odd == NULL) { odd = link; odd->next = link; list1 = list1->next; continue; } else { current = odd; while (current->next != odd) { current = current->next; } // Insert link at the end of the list current->next = link; link->next = odd; } list1 = list1->next; } } // Lets handle the last node link = (struct node*) malloc(sizeof(struct node)); link->data = list1->data; link->next = NULL; if (list1->data % 2 == 0) { current = even; while (current->next != even) { current = current->next; } // Insert link at the end of the list current->next = link; link->next = even; } else { current = odd; while (current->next != odd) { current = current->next; } // Insert link at the end of the list current->next = link; link->next = odd; } } int main() { int i; for (i = 1; i <= 10; i++) insert(i); printf("Complete list: n"); display(list); split_list(); printf("nOdd : "); display(odd); printf("Even : "); display(even); return 0; }
执行上面程序，得到以下结果 –
Complete list: [head] => 1 => 2 => 3 => 4 => 5 => 6 => 7 => 8 => 9 => 10 => [head] Odd : [head] => 1 => 3 => 5 => 7 => 9 => [head] Even : [head] => 2 => 4 => 6 => 8 => 10 => [head]
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