c ++ stl_通过分配另一个列表的所有元素来创建列表| C ++ STL

c ++ stl

There are two methods to implement it...

有两种方法可以实现它...

1 ) by assigning the existing list direct to the new list

1)通过直接将现有列表分配给新列表

    list<int> list2 = list1;

2 ) by using list::assign() function

2)通过使用list :: assign()函数

    list<int> list2;
list2.assign(list1.begin(), list1.end());

Example:

例：

In this example, we have a list list1 with 10 elements and we are creating another list list2, the elements of list2 will be assigning through the list1 by using list:assign() function, which is a library function of "list header". And, we are also creating a list list3 that is going to be assigned directly through the list1.

在这个例子中，我们有具有10个元素的列表list1的和我们正在创建另一个列表list2中，list2中的元素将通过使用列表中的列表1被分配：分配()函数，该函数是“列表头”的库函数。并且，我们还创建了一个列表list3 ，它将直接通过list1进行分配。

Program:

程序：

#include <iostream>
#include <list>
using namespace std;
//function to display the list
void dispList(list<int> L)
{
//declaring iterator to the list
list<int>::iterator l_iter;
for (l_iter = L.begin(); l_iter != L.end(); l_iter++)
cout<< *l_iter<< " ";
cout<<endl;
}
int main()
{
//list1 declaration
list<int> list1 = {10, 20, 30, 40, 50, 60, 70, 80, 90, 100};
//displaying list1
cout<<"Size of list1: "<<list1.size()<<endl;
cout<<"Elements of list1: ";
dispList(list1);
//declaring list2 and assigning the Elements
//of list1
list<int> list2;
list2.assign(list1.begin(), list1.end());
//displaying list2
cout<<"Size of list2: "<<list2.size()<<endl;
cout<<"Elements of list2: ";
dispList(list2);
//declaring list3 by assigning with list1
list<int> list3 = list1;
//displaying list3
cout<<"Size of list3: "<<list3.size()<<endl;
cout<<"Elements of list3: ";
dispList(list3);
return 0;
}

Output

输出量

Size of list1: 10
Elements of list1: 10 20 30 40 50 60 70 80 90 100
Size of list2: 10
Elements of list2: 10 20 30 40 50 60 70 80 90 100
Size of list3: 10
Elements of list3: 10 20 30 40 50 60 70 80 90 100