c语言数组-1
C programming Arrays (One-D Array, Two-D Array) Aptitude Questions and Answers : In this section you will find C Aptitude Questions and Answers on One Dimensional (1D) and Two Dimensional (2D) array.
C编程数组(一维数组，二维数组)能力问题：在本节中，您将找到关于一维(1D)和二维(2D)数组的C能力问题。
C编程数组(一维，二维)智能问题列表 (List of C programming Array (One, Two Dimensional) Aptitude Questions and Answers)
#include <stdio.h>
int main()
{
static int var[5];
int count=0;
var[++count]=++count;
for(count=0;count<5;count++)
printf("%d ",var[count]);
return 0;
}
0 1 0 0 0
0 2 0 0 0
0 0 2 0 0
0 0 0 0 0
0 0 2 0 0
0 1 0 0 0
0 2 0 0 0
0 0 2 0 0
0 0 0 0 0
0 0 2 0 0
#include <stdio.h>
int main()
{
int MAX=10;
int array[MAX];
printf("size of array is = %d",sizeof(array);
return 0;
}
size of array is = 20
size of array is = 40
size of array is = 4
Error
size of array is = 40
数组的大小= 20
数组的大小是= 40
数组的大小为= 4
错误
数组的大小是= 40
#include <stdio.h>
#define MAX 10
int main()
{ int array[MAX]={1,2,3},tally;
for(tally=0;tally< sizeof(array)/sizeof(int);tally+=1)
printf("%d ",*(tally+array));
return 0;
}
Error
1 3 4 5 6 7 8 9 10 11
1 2 3 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
1 2 3 0 0 0 0 0 0 0.
You can also access the array elements using *(counter_variable+array_name).
错误
1 3 4 5 6 7 8 9 10 11
1 2 3 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
1 2 3 0 0 0 0 0 0 0。
您还可以使用*(counter_variable + array_name)访问数组元素。
#include <stdio.h>
int main()
{ static int x[]={'A','B','C','D','E'},tally;
for(tally=0;tally< sizeof(x)/sizeof(int) ; tally+=1)
printf("%c,%c,%c\n",*(x+tally)+1,x[tally]+1,*(tally+x)+1);
return 0;
}
Error
A,A,A
B,B,B
C,C,C
D,D,D
E,E,EB,B,B
C,C,C
D,D,D
E,E,E
F,F,FE,E,E
D,D,D
C,C,C
B,B,B
A,A,A
B,B,B
C,C,C
D,D,D
E,E,E
F,F,F
错误
A，A，A
B，B，B
C，C，C
D，D，D
E，E，EB，B，B
C，C，C
D，D，D
E，E，E
F，F，FE，E，E
D，D，D
C，C，C
B，B，B
A，A，A
B，B，B
C，C，C
D，D，D
E，E，E
F，F，F
#include <stdio.h>
int main()
{ static int array[]={10,20,30,40,50};
printf("%d...%d",*array,*(array+3)* *array);
return 0;
}
Error
10...40
10...300
10....400
10...400
In expression printf("%d...%d",*array,*(array+3)* *array);, *array is 10, *(array+3) is 40.
错误
10 ... 40
10 ... 300
10 .... 400
10 ... 400
在表达式中printf(“％d ...％d”，* array，*(array + 3)* * array); ，* array是10 ，*(array + 3)是40 。
#include <stdio.h>
int main()
{ int a[5]={1,2,3,4,5},b[5]={10,20,30,40,50},tally;
for(tally=0;tally< 5;++tally)
*(a+tally)=*(tally+a)+ *(b+tally);
for(tally=0;tally< 5;tally++)
printf("%d ",*(a+tally));
return 0;
}
1 2 3 4 5
10 20 30 40 50
11 22 33 44 55
Error
11 22 33 44 55
This is a simple program to add elements of two arrays, you can access array elements using *(tally+a) Or *(b+tally) Or a[tally] .
1 2 3 4 5
10 20 30 40 50
11 22 33 44 55
错误
11 22 33 44 55
这是一个添加两个数组元素的简单程序，您可以使用*(tally + a)或*(b + tally)或a [tally]访问数组元素。
#include <stdio.h>
int main()
{ int a[5]={0x00,0x01,0x02,0x03,0x04},i;
i=4;
while(a[i])
{
printf("%02d ",*a+i);
--i;
}
return 0;
}
00 01 02 03 04
04 03 02 01 00
04 03 02 01
01 02 03 04
04 03 02 01
0x00,0x01,0x02,0x03,0x04,0x05 are hex values of 0,1,2,3,4,5.
while(a[i]) will be terminated by a[0], becuase value of a[0] is 0 hence, 04,03,03,01 will print.
00 01 02 03 04
04 03 02 01 00
04 03 02 01
01 02 03 04
04 03 02 01
0x00,0x01,0x02,0x03,0x04,0x05是十六进制值0、1、2、3、4、5。
while(a [i])将以a [0]终止，因为a [0]的值为0，因此将打印04、03、03、01。
#include <stdio.h>
int main()
{
char X[10]={'A'},i;
for(i=0; i<10; i++)
printf("%d ",X[i]);
return 0;
}
A 0 0 0 0 0 0 0 0 0
A
A 32 32 32 32 32 32 32 32 32
ERROR
A 0 0 0 0 0 0 0 0 0
char X[10]={'A'}; 0th index of X is assigned by 'A' and rest of elements is assigned by 0.
A 0 0 0 0 0 0 0 0 0
一个
A 32 32 32 32 32 32 32 32 32
错误
A 0 0 0 0 0 0 0 0 0
字符X [10] = {'A'}; X的第 0 个索引由“ A”分配，其余元素由0分配。
int x[5];
int x[5]={1,2,3,4,5};
int x[5]={1,2};
int x[];
int x[];
You can ignore value within the subscript [] when you are initialising array with elements, but here no initialisation found.
int x [5];
int x [5] = {1,2,3,4,5};
int x [5] = {1,2};
int x [];
int x [];
当您使用元素初始化数组时，可以忽略下标[]中的值，但是在此找不到初始化。
翻译自: https://www.includehelp.com/c-programs/c-arrays-aptitude-questions-and-answers.aspx
c语言数组-1
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