table1idname1a2b3ctable2idnamecont1aaa2bbb3aaaaaSELECT*,count(distincttable2.name)FROMtable1,table2WHEREtable1.name=table2.nameGROUPBYtable2.nameORDERBYtable2.idDESC";重复...

table1

id name

1 a

2 b

3 c

table2

id name cont

1 a aa

2 b bb

3 a aaaa

SELECT *,count(distinct table2.name) FROM table1,table2 WHERE table1.name = table2.name GROUP BY table2.name ORDER BY table2.id DESC";

重复的记录是过滤掉了，现在问题是我要的是table2中重复的name=a的ID最大的cont=aaaa的内容。

每次读出来的都是name=a ,cont=aa的内容。。。

$sqlcha ="SELECT *,count(distinct crm_followinfo.FOL_Comname) FROM crm_customers,crm_followinfo WHERE crm_customers.CUS_Comname = crm_followinfo.FOL_Comname GROUP BY crm_followinfo.FOL_Comname ORDER BY FOL_Id DESC";

$query_limit_Recordset1 = sprintf("%s LIMIT %d, %d", $sqlcha, $startRow_Recordset1, $maxRows_Recordset1);

$connn = mysql_query($query_limit_Recordset1, $conn) or die(mysql_error());

$row_Recordset1 = mysql_fetch_assoc($connn);

在这个表crm_followinfo 有个FOL_Id字段 ， 如何除掉重复后，显示最大的FOL_Id的这条记录呢？

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