与Play Framework 2.0一起使用发布的值而不定义表单映射，可能不像Play 1.x那样明显，这就是为什么我要编写此快速备忘单。

对于此快速示例，让我们定义以下视图：

app / views / index.scala.html

@(message: String)message: @message <br /><h2>Scala form</h2><form action="@routes.ScalaPoster.save()" method="POST">scala name: <input name="scala_name"> <br />scala surname: <input name="scala_surname"> <br /><input type="submit" value="save">
</form><h2>Java form</h2><form action="@routes.JavaPoster.save()" method="POST">java name: <input name="java_name"> <br />java surname: <input name="java_surname"> <br /><input type="submit" value="save">
</form>

和以下路由文件：

conf /路由

# Home page
GET     /                         controllers.Application.indexPOST    /scala                    controllers.ScalaPoster.save
POST    /java                     controllers.JavaPoster.save

使用Java，直接访问请求正文：

app / controllers / JavaPoster.java

package controllers;import play.mvc.*;import views.html.*;import java.util.Map;public class JavaPoster extends Controller {public static Result save() {final Map<String, String[]> values = request().body().asFormUrlEncoded();final String name = values.get("java_name")[0];final String surname = values.get("java_surname")[0];return ok(index.render(String.format("You are %s, %s",surname, name)));}}

或使用DynamicForm：

package controllers;import play.mvc.*;import views.html.*;import play.data.DynamicForm;public class JavaPoster extends Controller {public static Result save() {final DynamicForm form = form().bindFromRequest();final String name = form.get("java_name");final String surname = form.get("java_surname");return ok(index.render(String.format("You are %s, %s",surname, name)));}}

现在是scala版本，可以访问主体：

app / controllers / ScalaPoster.java

package controllersimport play.api.mvc._object ScalaPoster extends Controller {def save = Action { request =>def name = request.body.asFormUrlEncoded.get("scala_name")(0)def surname = request.body.asFormUrlEncoded.get("scala_surname")(0)Ok(views.html.index("You are %s, %s".format(surname, name))) }}

并定义一个表格

package controllersimport play.api.mvc._import play.api.data.Form
import play.api.data.Forms.tuple
import play.api.data.Forms.textobject ScalaPoster extends Controller {val form = Form(tuple("scala_name" -> text,"scala_surname" -> text))def save = Action { implicit request =>def values = form.bindFromRequest.datadef name = values("scala_name")def surname = values("scala_surname")Ok(views.html.index("You are %s, %s".format(surname, name))) }}

请注意上述示例中的隐式请求。 您可以将其显式传递给bindFromRequest

def values = form.bindFromRequest()(request).data

您也可以玩元组并发出类似

val data = form.bindFromRequest.getOk(views.html.index("You are %s, %s".format(data._2, data._1)))

要么

val (name, surname) = form.bindFromRequest.getOk(views.html.index("You are %s, %s".format(surname, name)))

当然，如果您只想读取一个过帐值，可以发出：

def name = Form("scala_name" -> text).bindFromRequest.get

有几种方法可以实现它。 希望这对您有所帮助。

参考： Play Framework发布了我们的JCG合作伙伴 Sebastian Scarano在“ 玩转Play框架”中 重新审视的价值观 ！ 博客。